The function [tex]$h(x)$[/tex] is given below:
[tex]\[ h(x)=\{(3,-5),(5,-7),(6,-9),(10,-12),(12,-16)\} \][/tex]

Which of the following gives [tex]$h^{-1}(x)$[/tex]?

A. [tex]\[ \{(3,5),(5,7),(6,9),(10,12),(12,16)\} \][/tex]

B. [tex]\[ \{(-5,3),(-7,5),(-9,6),(-12,10),(-16,12)\} \][/tex]

C. [tex]\[ \{(3,-5),(5,-7),(6,-9),(10,-12),(12,-16)\} \][/tex]

D. [tex]\[ \{(5,3),(7,5),(9,6),(12,10),(16,12)\} \][/tex]



Answer :

To solve this problem, we need to find the inverse function [tex]\( h^{-1}(x) \)[/tex] from the given function [tex]\( h(x) \)[/tex].

The function [tex]\( h(x) \)[/tex] is defined as:
[tex]\[ h(x) = \{(3, -5), (5, -7), (6, -9), (10, -12), (12, -16)\} \][/tex]

The inverse function [tex]\( h^{-1}(x) \)[/tex] is obtained by swapping each pair of the function [tex]\( h(x) \)[/tex]. For each pair [tex]\((a, b)\)[/tex] in [tex]\( h(x) \)[/tex], the corresponding pair in [tex]\( h^{-1}(x) \)[/tex] will be [tex]\((b, a)\)[/tex].

Let’s perform this swapping step-by-step for each pair in [tex]\( h(x) \)[/tex]:

1. For the pair [tex]\( (3, -5) \)[/tex], the swapped pair is [tex]\( (-5, 3) \)[/tex].
2. For the pair [tex]\( (5, -7) \)[/tex], the swapped pair is [tex]\( (-7, 5) \)[/tex].
3. For the pair [tex]\( (6, -9) \)[/tex], the swapped pair is [tex]\( (-9, 6) \)[/tex].
4. For the pair [tex]\( (10, -12) \)[/tex], the swapped pair is [tex]\( (-12, 10) \)[/tex].
5. For the pair [tex]\( (12, -16) \)[/tex], the swapped pair is [tex]\( (-16, 12) \)[/tex].

Thus, the inverse function [tex]\( h^{-1}(x) \)[/tex] is given by:
[tex]\[ h^{-1}(x) = \{(-5, 3), (-7, 5), (-9, 6), (-12, 10), (-16, 12)\} \][/tex]

Now let's evaluate the given options:

1. [tex]\(\{(3, 5), (5, 7), (6, 9), (10, 12), (12, 16)\}\)[/tex]
2. [tex]\(\{(-5, 3), (-7, 5), (-9, 6), (-12, 10), (-16, 12)\}\)[/tex]
3. [tex]\(\{(3, -5), (5, -7), (6, -9), (10, -12), (12, -16)\}\)[/tex]
4. [tex]\(\{(5, 3), (7, 5), (9, 6), (12, 10), (16, 12)\}\)[/tex]

Based on our calculations, the correct answer is:
[tex]\[ \{(-5, 3), (-7, 5), (-9, 6), (-12, 10), (-16, 12)\} \][/tex]

Therefore, the option that gives [tex]\( h^{-1}(x) \)[/tex] is:
[tex]\[ \boxed{\{(-5, 3), (-7, 5), (-9, 6), (-12, 10), (-16, 12)\}} \][/tex]