To determine the net ionic equation for the given reaction, we need to follow these steps:
1. Write down the full ionic equation:
The given chemical reaction is:
[tex]\[
Na^+ + C_2H_3O_2^-(aq) + H^+ + Cl^- \longrightarrow Na^+ + Cl^- + HC_2H_3O_2
\][/tex]
2. Identify the spectator ions:
Spectator ions are ions that appear on both the reactant and product sides of the equation and do not undergo any chemical change. Here, we identify:
- [tex]\( Na^+ \)[/tex] is present on both sides.
- [tex]\( Cl^- \)[/tex] is present on both sides as well.
3. Remove the spectator ions:
By eliminating [tex]\( Na^+ \)[/tex] and [tex]\( Cl^- \)[/tex] from the equation, we focus on the ions that actually participate in the reaction.
4. Write the net ionic equation:
After removing the spectator ions, we are left with:
[tex]\[
C_2H_3O_2^-(aq) + H^+ \longrightarrow HC_2H_3O_2
\][/tex]
Therefore, the net ionic equation for the reaction is:
[tex]\[
C_2H_3O_2^-(aq) + H^+ \longrightarrow HC_2H_3O_2
\][/tex]
Thus, the correct choice from the given options is:
[tex]\[
C_2H_3O_2^-(aq) + H^+ \longrightarrow HC_2H_3O_2
\][/tex]