Frosty0110
Answered

Consider the total ionic equation below.

[tex]\[ 2 H ^{+} + CrO_4^{2-} + Ba^{2+} + 2 OH^{-} \longrightarrow Ba^{2+} + CrO_4^{2-} + 2 H_2O \][/tex]

What are the spectator ions in this equation?

A. [tex]\( H^{+} \)[/tex] and [tex]\( OH^{-} \)[/tex]

B. [tex]\( H^{+} \)[/tex] and [tex]\( Ba^{2+} \)[/tex]

C. [tex]\( CrO_4^{2-} \)[/tex] and [tex]\( OH^{-} \)[/tex]

D. [tex]\( CrO_4^{2-} \)[/tex] and [tex]\( Ba^{2+} \)[/tex]



Answer :

GinnyAnswer
To identify the spectator ions in the total ionic equation, we need to look for ions that remain unchanged on both the reactant and product sides of the equation. Spectator ions are ions that do not participate in the chemical reaction and remain in the same form before and after the reaction.

Given the total ionic equation:
[tex]\[ 2 H^+ + CrO_4^{2-} + Ba^{2+} + 2 OH^- \rightarrow Ba^{2+} + CrO_4^{2-} + 2 H_2O \][/tex]

Let's analyze the reactants and products:

### Reactants:
1. [tex]\( 2 H^+ \)[/tex]
2. [tex]\( CrO_4^{2-} \)[/tex]
3. [tex]\( Ba^{2+} \)[/tex]
4. [tex]\( 2 OH^- \)[/tex]

### Products:
1. [tex]\( Ba^{2+} \)[/tex]
2. [tex]\( CrO_4^{2-} \)[/tex]
3. [tex]\( 2 H_2O \)[/tex]

### Step-by-Step Analysis
1. Identify ions present on both sides:
- [tex]\( H^+ \)[/tex] is present in the reactants but not in the products (it forms water).
- [tex]\( CrO_4^{2-} \)[/tex] is present in both the reactants and the products.
- [tex]\( Ba^{2+} \)[/tex] is present in both the reactants and the products.
- [tex]\( OH^- \)[/tex] is present in the reactants but not in the products (it forms water).

2. Determine which ions remain unchanged:
- [tex]\( CrO_4^{2-} \)[/tex] remains unchanged on both sides.
- [tex]\( Ba^{2+} \)[/tex] remains unchanged on both sides.

### Conclusion
The ions that remain unchanged and do not participate in the chemical reaction are [tex]\( CrO_4^{2-} \)[/tex] and [tex]\( Ba^{2+} \)[/tex]. These are the spectator ions.

Therefore, the correct answer is:
[tex]\[ \boxed{CrO_4^{2-} \text{ and } Ba^{2+}} \][/tex]

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