Examine the table.

\begin{tabular}{|c|c|c|c|}
\hline
Element & \begin{tabular}{c}
Number of \\
Protons
\end{tabular} & \begin{tabular}{c}
Number of \\
Neutrons
\end{tabular} & \begin{tabular}{c}
Number of \\
Electrons
\end{tabular} \\
\hline
lead [tex]$(Pb)$[/tex] & 82 & 125 & 82 \\
\hline
radon [tex]$(Rn)$[/tex] & 86 & 136 & 86 \\
\hline
uranium [tex]$(U)$[/tex] & 92 & 146 & 92 \\
\hline
francium [tex]$(Fr)$[/tex] & 87 & 136 & 87 \\
\hline
\end{tabular}

Which element has the smallest atomic mass?

A. uranium

B. radon

C. lead

D. francium



Answer :

To determine which element has the smallest atomic mass, we need to examine the number of protons and neutrons for each element and sum them up, as the atomic mass is effectively the sum of protons and neutrons.

Let's calculate the atomic masses step by step for each element:

1. Lead (Pb):
- Number of Protons = 82
- Number of Neutrons = 125
- Atomic Mass = Protons + Neutrons = 82 + 125 = 207

2. Radon (Rn):
- Number of Protons = 86
- Number of Neutrons = 136
- Atomic Mass = Protons + Neutrons = 86 + 136 = 222

3. Uranium (U):
- Number of Protons = 92
- Number of Neutrons = 146
- Atomic Mass = Protons + Neutrons = 92 + 146 = 238

4. Francium (Fr):
- Number of Protons = 87
- Number of Neutrons = 136
- Atomic Mass = Protons + Neutrons = 87 + 136 = 223

Now, let's compare the calculated atomic masses:

- Lead (Pb) = 207
- Radon (Rn) = 222
- Uranium (U) = 238
- Francium (Fr) = 223

Among these, the element with the smallest atomic mass is Lead (Pb), with an atomic mass of 207.

Therefore, the element with the smallest atomic mass is Lead (Pb).