Answer :
To solve the problem [tex]\(16.43 - 1.043\)[/tex], we can follow these steps:
1. Align the decimal points: It helps to write the numbers in a way that aligns the decimal points vertically.
[tex]\[ \begin{array}{r} 16.430 \\ -1.043 \\ \hline \end{array} \][/tex]
2. Subtract each column from right to left:
- Starting from the rightmost column, subtract the thousandths:
[tex]\[ 0 - 3 = -3 \][/tex]
Since [tex]\(0\)[/tex] is smaller than [tex]\(3\)[/tex], we need to borrow from the next column.
- Move to the hundredths column. Borrow 1 from the hundredths column:
[tex]\[ 3 - 1 = 2 \quad \rightarrow \quad (10) - 3 = 7 \text{ (borrowed from the next place value)} \][/tex]
So, we have:
[tex]\[ \begin{array}{r} 16.430 \\ -1.043 \\ \hline 15.387 \end{array} \][/tex]
3. Combine the remaining steps to handle the rest of the columns similarly:
- Tenths column:
[tex]\[ 3 - 4 = -1 \rightarrow (borrow 1 to make 13 - 4 = 9) \][/tex]
- Tens column:
[tex]\[ If we need to adjust we get, 6 - 1 = 5 \][/tex]
Putting it all together:
[tex]\[ \begin{array}{r} 15 \\ -1 \\ \hline 15.387 \end{array} \][/tex]
Therefore, the value of [tex]\( 16.43 - 1.043 \)[/tex] is:
[tex]\[ \boxed{15.387} \][/tex]
1. Align the decimal points: It helps to write the numbers in a way that aligns the decimal points vertically.
[tex]\[ \begin{array}{r} 16.430 \\ -1.043 \\ \hline \end{array} \][/tex]
2. Subtract each column from right to left:
- Starting from the rightmost column, subtract the thousandths:
[tex]\[ 0 - 3 = -3 \][/tex]
Since [tex]\(0\)[/tex] is smaller than [tex]\(3\)[/tex], we need to borrow from the next column.
- Move to the hundredths column. Borrow 1 from the hundredths column:
[tex]\[ 3 - 1 = 2 \quad \rightarrow \quad (10) - 3 = 7 \text{ (borrowed from the next place value)} \][/tex]
So, we have:
[tex]\[ \begin{array}{r} 16.430 \\ -1.043 \\ \hline 15.387 \end{array} \][/tex]
3. Combine the remaining steps to handle the rest of the columns similarly:
- Tenths column:
[tex]\[ 3 - 4 = -1 \rightarrow (borrow 1 to make 13 - 4 = 9) \][/tex]
- Tens column:
[tex]\[ If we need to adjust we get, 6 - 1 = 5 \][/tex]
Putting it all together:
[tex]\[ \begin{array}{r} 15 \\ -1 \\ \hline 15.387 \end{array} \][/tex]
Therefore, the value of [tex]\( 16.43 - 1.043 \)[/tex] is:
[tex]\[ \boxed{15.387} \][/tex]