If using the method of completing the square to solve the quadratic equation [tex]$x^2 - 9x - 26 = 0$[/tex], which number would have to be added to "complete the square"?



Answer :

To solve the quadratic equation [tex]\( x^2 - 9x - 26 = 0 \)[/tex] by completing the square, follow these steps:

1. Move the constant term to the other side of the equation:
[tex]\[ x^2 - 9x = 26 \][/tex]

2. Identify the coefficient of the [tex]\( x \)[/tex] term, which is [tex]\(-9\)[/tex].

3. Take half of this coefficient.
[tex]\[ \text{Half of } -9 \text{ is } -\frac{9}{2} \][/tex]

4. Square this half-coefficient to find the number that needs to be added to both sides to complete the square.
[tex]\[ \left( -\frac{9}{2} \right)^2 = \left( \frac{9}{2} \right)^2 = \frac{81}{4} = 20.25 \][/tex]

Therefore, the number that needs to be added to both sides of the equation to complete the square is [tex]\( 20.25 \)[/tex].