noboa7
Answered

What is the quotient of [tex]\frac{-8 x^6}{4 x^{-3}}[/tex]?

A. [tex]\frac{x^9}{32}[/tex]
B. [tex]4 x^9[/tex]
C. [tex]-\frac{12}{x^2}[/tex]
D. [tex]-2 x^9[/tex]



Answer :

To find the quotient for the expression [tex]\(\frac{-8 x^6}{4 x^{-3}}\)[/tex], let's break it down step-by-step.

1. Simplify the Constants:

We have [tex]\(\frac{-8}{4}\)[/tex] from the constants in the numerator and denominator.

[tex]\[ \frac{-8}{4} = -2 \][/tex]

2. Simplify the Exponents on [tex]\( x \)[/tex]:

We need to divide [tex]\( x^6 \)[/tex] by [tex]\( x^{-3} \)[/tex]. We do this by subtracting the exponent in the denominator from the exponent in the numerator:

[tex]\[ x^6 \div x^{-3} = x^{6 - (-3)} = x^{6 + 3} = x^9 \][/tex]

3. Combine the Simplified Parts:

Now, we combine the simplified constant part with the simplified exponent part:

[tex]\[ -2 \times x^9 = -2 x^9 \][/tex]

Therefore, the quotient of [tex]\(\frac{-8 x^6}{4 x^{-3}}\)[/tex] is:

[tex]\[ -2 x^9 \][/tex]

So, the correct answer is:

[tex]\[ \boxed{-2 x^9} \][/tex]