noboa7
Answered

Which expression is equivalent to [tex]\frac{2x^2 + 2x - 4}{2x^2 - 4x + 2}[/tex]?

A. [tex]\frac{x+2}{x-1}[/tex]
B. [tex]x+2[/tex]
C. [tex]-2[/tex]
D. [tex]\frac{x+2}{x-2}[/tex]



Answer :

To determine which expression is equivalent to [tex]\(\frac{2 x^2 + 2 x - 4}{2 x^2 - 4 x + 2}\)[/tex], we need to simplify the given fraction.

Starting with the fraction:

[tex]\[ \frac{2 x^2 + 2 x - 4}{2 x^2 - 4 x + 2} \][/tex]

We factorize both the numerator and the denominator:

1. Factorize the Numerator:

The numerator is [tex]\(2x^2 + 2x - 4\)[/tex].

First, factor out the greatest common factor (GCF), which is 2:

[tex]\[ 2(x^2 + x - 2) \][/tex]

Next, factor the quadratic expression [tex]\(x^2 + x - 2\)[/tex]:

[tex]\[ x^2 + x - 2 = (x + 2)(x - 1) \][/tex]

So, the numerator becomes:

[tex]\[ 2(x + 2)(x - 1) \][/tex]

2. Factorize the Denominator:

The denominator is [tex]\(2x^2 - 4x + 2\)[/tex].

First, factor out the GCF, which is 2:

[tex]\[ 2(x^2 - 2x + 1) \][/tex]

Next, factor the quadratic expression [tex]\(x^2 - 2x + 1\)[/tex]:

[tex]\[ x^2 - 2x + 1 = (x - 1)^2 \][/tex]

So, the denominator becomes:

[tex]\[ 2(x - 1)^2 \][/tex]

3. Simplify the Fraction:

Putting the factored forms together, we have:

[tex]\[ \frac{2(x + 2)(x - 1)}{2(x - 1)^2} \][/tex]

We can cancel the common factors in the numerator and the denominator:

[tex]\[ \frac{2 \cdot (x + 2) \cdot (x - 1)}{2 \cdot (x - 1) \cdot (x - 1)} = \frac{(x + 2)}{(x - 1)} \][/tex]

Thus, the simplified expression is:

[tex]\[ \frac{x + 2}{x - 1} \][/tex]

Therefore, the equivalent expression is [tex]\(\frac{x+2}{x-1}\)[/tex].

Among the given choices, the correct answer is:

[tex]\[ \boxed{\frac{x+2}{x-1}} \][/tex]