noboa7
Answered

Simplify the expression below:

[tex]\[ \left(\frac{2n}{6n+4}\right)\left(\frac{3n+2}{3n-2}\right) \][/tex]

What is the numerator of the simplified expression?



Answer :

To simplify the given expression:

[tex]\[ \left( \frac{2n}{6n + 4} \right) \left( \frac{3n + 2}{3n - 2} \right) \][/tex]

we can follow these steps:

### Step 1: Simplify each fraction separately

#### Simplify the first fraction [tex]\(\frac{2n}{6n + 4}\)[/tex]:

1. Factor out the greatest common divisor (GCD) in the denominator:
[tex]\[ 6n + 4 = 2(3n + 2) \][/tex]

2. Rewrite the fraction:
[tex]\[ \frac{2n}{2(3n + 2)} = \frac{2n}{2} \cdot \frac{1}{3n + 2} \][/tex]

3. Simplify by canceling the common factor of 2:
[tex]\[ \frac{n}{3n + 2} \][/tex]

So, the simplified form of the first fraction is:
[tex]\[ \frac{n}{3n + 2} \][/tex]

#### Simplify the second fraction [tex]\(\frac{3n + 2}{3n - 2}\)[/tex]:

1. The second fraction is already in its simplest form, so we leave it as:
[tex]\[ \frac{3n + 2}{3n - 2} \][/tex]

### Step 2: Multiply the simplified fractions

Now, multiply the simplified fractions:
[tex]\[ \left( \frac{n}{3n + 2} \right) \left( \frac{3n + 2}{3n - 2} \right) \][/tex]

1. The [tex]\(3n + 2\)[/tex] terms in the numerator of the second fraction and the denominator of the first fraction will cancel each other out:
[tex]\[ \frac{n \cdot (3n + 2)}{(3n + 2) \cdot (3n - 2)} = \frac{n}{3n - 2} \][/tex]

### Step 3: Identify the numerator of the simplified expression

The final simplified fraction is:
[tex]\[ \frac{n}{3n - 2} \][/tex]

Thus, the numerator of the simplified expression is:
[tex]\[ n \][/tex]