Suppose a [tex]$0.6 \, \text{kg}$[/tex] ball is hit with a force of [tex]$12 \, \text{N}$[/tex]. What will be its acceleration?



Answer :

Certainly! Let's determine the acceleration of a 0.6 kg ball when it is hit with a force of 12 N by using Newton's second law of motion.

### Step-by-Step Solution

1. Understand Newton's Second Law: Newton's second law states that the force applied to an object is equal to the mass of the object multiplied by the acceleration. Mathematically, this can be expressed as:
[tex]\[ F = m \cdot a \][/tex]
where:
- [tex]\( F \)[/tex] is the force applied (in Newtons, N),
- [tex]\( m \)[/tex] is the mass of the object (in kilograms, kg),
- [tex]\( a \)[/tex] is the acceleration (in meters per second squared, m/s²).

2. Identify the Given Values:
- The mass ([tex]\( m \)[/tex]) of the ball is 0.6 kg.
- The force ([tex]\( F \)[/tex]) applied to the ball is 12 N.

3. Rearrange the Formula to Solve for Acceleration: To find the acceleration ([tex]\( a \)[/tex]), we need to rearrange the formula [tex]\( F = m \cdot a \)[/tex] to solve for [tex]\( a \)[/tex]. This gives:
[tex]\[ a = \frac{F}{m} \][/tex]

4. Substitute the Given Values into the Rearranged Formula:
- Force [tex]\( F = 12 \)[/tex] N
- Mass [tex]\( m = 0.6 \)[/tex] kg

Now, substitute these values into the equation:
[tex]\[ a = \frac{12 \text{ N}}{0.6 \text{ kg}} \][/tex]

5. Calculate the Acceleration:
[tex]\[ a = \frac{12}{0.6} = 20 \text{ m/s}^2 \][/tex]

The acceleration of the ball when hit with a force of 12 N is [tex]\( 20 \text{ m/s}^2 \)[/tex].