Answer :
To address the research question using a one-way ANOVA, we need to determine if there are significant differences in improvements in depression scores among the four groups: Low, High, Moderately Severe, and Severe. Let's conduct our one-way ANOVA step by step.
### Step-by-Step Solution:
1. State the Hypotheses:
- Null Hypothesis ([tex]\(H_0\)[/tex]): There are no significant differences in the means of improvement across the four groups.
- Alternative Hypothesis ([tex]\(H_a\)[/tex]): At least one group mean improvement is significantly different from the others.
2. Collect the Data:
- Low: [tex]\( [1.5, 2.4, 1.7, 1.4, 2.0, 3.9] \)[/tex]
- High: [tex]\( [1.2, 1.7, 4.2, 3.6, 1.8, 3.8] \)[/tex]
- Moderately Severe: [tex]\( [2.7, 2.2, 4.0, 2.8, 3.9, 3.4] \)[/tex]
- Severe: [tex]\( [4.4, 4.4, 3.5, 3.6, 4.9, 2.0] \)[/tex]
3. Calculate the ANOVA:
- Using an appropriate statistical method (typically within a software or a calculator designed for statistical computation such as SPSS, R, or Python's `scipy.stats` library), we compute the F-ratio and the p-value.
4. F-ratio and p-value Results:
- F-ratio: Rounded to three decimal places, the F-ratio is 2.851.
- p-value: Rounded to three decimal places, the p-value is 0.063.
5. Interpret the Results:
- F-ratio: The F-statistic is a measure of the variance between the group means relative to the variance within the groups. Typically, higher F-values suggest that the group means are not all the same.
- p-value: The p-value indicates the probability of observing the test statistic or more extreme when the null hypothesis is true. A common significance level [tex]\(\alpha\)[/tex] is 0.05. Since the p-value (0.063) is slightly higher than 0.05, we do not have enough evidence to reject the null hypothesis at the [tex]\( \alpha = 0.05 \)[/tex] level.
### Conclusion:
There is not enough statistical evidence at the 0.05 significance level to say that there is a significant difference in the mean improvements in depression scores among the four levels of depression severity.
### Final Answers:
- F-ratio: [tex]\(2.851\)[/tex]
- p-value: [tex]\(0.063\)[/tex]
These results suggest that, while there appear to be some differences in the mean improvements, these differences are not statistically significant based on the ANOVA test conducted.
### Step-by-Step Solution:
1. State the Hypotheses:
- Null Hypothesis ([tex]\(H_0\)[/tex]): There are no significant differences in the means of improvement across the four groups.
- Alternative Hypothesis ([tex]\(H_a\)[/tex]): At least one group mean improvement is significantly different from the others.
2. Collect the Data:
- Low: [tex]\( [1.5, 2.4, 1.7, 1.4, 2.0, 3.9] \)[/tex]
- High: [tex]\( [1.2, 1.7, 4.2, 3.6, 1.8, 3.8] \)[/tex]
- Moderately Severe: [tex]\( [2.7, 2.2, 4.0, 2.8, 3.9, 3.4] \)[/tex]
- Severe: [tex]\( [4.4, 4.4, 3.5, 3.6, 4.9, 2.0] \)[/tex]
3. Calculate the ANOVA:
- Using an appropriate statistical method (typically within a software or a calculator designed for statistical computation such as SPSS, R, or Python's `scipy.stats` library), we compute the F-ratio and the p-value.
4. F-ratio and p-value Results:
- F-ratio: Rounded to three decimal places, the F-ratio is 2.851.
- p-value: Rounded to three decimal places, the p-value is 0.063.
5. Interpret the Results:
- F-ratio: The F-statistic is a measure of the variance between the group means relative to the variance within the groups. Typically, higher F-values suggest that the group means are not all the same.
- p-value: The p-value indicates the probability of observing the test statistic or more extreme when the null hypothesis is true. A common significance level [tex]\(\alpha\)[/tex] is 0.05. Since the p-value (0.063) is slightly higher than 0.05, we do not have enough evidence to reject the null hypothesis at the [tex]\( \alpha = 0.05 \)[/tex] level.
### Conclusion:
There is not enough statistical evidence at the 0.05 significance level to say that there is a significant difference in the mean improvements in depression scores among the four levels of depression severity.
### Final Answers:
- F-ratio: [tex]\(2.851\)[/tex]
- p-value: [tex]\(0.063\)[/tex]
These results suggest that, while there appear to be some differences in the mean improvements, these differences are not statistically significant based on the ANOVA test conducted.