Answered

The additional growth of plants in one week is recorded for 11 plants, with a sample standard deviation of 3 inches and a sample mean of 8 inches.

Find the following:

1. [tex]\( t^* \)[/tex] at the 0.05 significance level:
Example: 1.234

2. Margin of error:
Example: 1.234

3. Confidence interval:
[tex]\([ \text{smaller value}, \text{larger value} ]\)[/tex]
Example: [tex]\([ 12.345, 12.345 ]\)[/tex]



Answer :

GinnyAnswer
Sure, let's walk through a detailed step-by-step solution to determine the critical t-value, the margin of error, and the 95% confidence interval for the additional growth of plants.

### Step-by-Step Solution

#### Step 1: Understand the Given Data
We are provided with:
- Sample size ([tex]\( n \)[/tex]) = 11
- Sample mean ([tex]\( \bar{x} \)[/tex]) = 8 inches
- Sample standard deviation ([tex]\( s \)[/tex]) = 3 inches
- Significance level ([tex]\( \alpha \)[/tex]) = 0.05

#### Step 2: Calculate the Degrees of Freedom (df)
Degrees of freedom is calculated as:
[tex]\[ df = n - 1 = 11 - 1 = 10 \][/tex]

#### Step 3: Determine the Critical t-Value ([tex]\( t^ \)[/tex])
The critical t-value at a 0.05 significance level for a two-tailed test can be found using the desired confidence level (1 - [tex]\( \alpha \)[/tex]). Since [tex]\( \alpha = 0.05 \)[/tex], this corresponds to a 95% confidence level.

For [tex]\( df = 10 \)[/tex] and a 95% confidence level:
[tex]\[ t^ = 2.228 \][/tex]

#### Step 4: Calculate the Margin of Error
The margin of error (ME) can be calculated using the formula:
[tex]\[ \text{ME} = t^ \times \left( \frac{s}{\sqrt{n}} \right) \][/tex]
Substitute the values:
- [tex]\( t^ = 2.228 \)[/tex]
- [tex]\( s = 3 \)[/tex]
- [tex]\( n = 11 \)[/tex]

[tex]\[ \text{ME} = 2.228 \times \left( \frac{3}{\sqrt{11}} \right) \approx 2.015 \][/tex]

#### Step 5: Calculate the Confidence Interval
The confidence interval (CI) can be calculated using the sample mean ([tex]\( \bar{x} \)[/tex]) and the margin of error (ME):
[tex]\[ \text{CI} = \left( \bar{x} - \text{ME}, \bar{x} + \text{ME} \right) \][/tex]

Substitute the values:
- [tex]\( \bar{x} = 8 \)[/tex]
- [tex]\( \text{ME} = 2.015 \)[/tex]

[tex]\[ \text{CI} = \left( 8 - 2.015, 8 + 2.015 \right) = (5.985, 10.015) \][/tex]

### Summary
- [tex]\( t^* \)[/tex] at the 0.05 significance level = 2.228
- Margin of error = 2.015
- Confidence interval = [5.985, 10.015]

So, the additional growth of plants in one week can be estimated with 95% confidence to lie between 5.985 inches and 10.015 inches.

Other Questions