Write the given expression as a single trigonometric function.

[tex]\[
\frac{\tan(57^\circ) - \tan(21^\circ)}{1 + \tan(57^\circ) \tan(21^\circ)} = \square
\][/tex]

(Note: The expression inside the box should be filled in with the correct single trigonometric function).



Answer :

Sure! Let's simplify the given expression step-by-step using trigonometric identities.

We are given the expression:
[tex]$ \frac{\tan(57^\circ) - \tan(21^\circ)}{1 + \tan(57^\circ) \tan(21^\circ)} $[/tex]

First, recall the tangent subtraction identity:
[tex]$ \tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B} $[/tex]

Here, [tex]\( A = 57^\circ \)[/tex] and [tex]\( B = 21^\circ \)[/tex]. Therefore, by directly using this identity, we have:
[tex]$ \tan(57^\circ - 21^\circ) $[/tex]

Now, subtract the angles inside the tangent function:
[tex]$ 57^\circ - 21^\circ = 36^\circ $[/tex]

So, the expression can be simplified to:
[tex]$ \tan(36^\circ) $[/tex]

Thus, the given expression as a single trigonometric function is:
[tex]$ \tan(36^\circ) $[/tex]