Alright, let's tackle the given problem step by step.
1. 100 drops of water fall from a burette. The initial and final readings are 39.0 cm³ and 41.5 cm³ respectively.
i. What is the average volume of one drop?
To find the average volume of one drop, we first need to determine the total volume of water that fell. This can be calculated by subtracting the initial burette reading from the final burette reading:
[tex]\[
\text{Total volume of water} = \text{Final reading} - \text{Initial reading} = 41.5 \, \text{cm}^3 - 39.0 \, \text{cm}^3 = 2.5 \, \text{cm}^3
\][/tex]
Next, to find the average volume of one drop, we divide the total volume by the number of drops:
[tex]\[
\text{Average volume per drop} = \frac{\text{Total volume of water}}{\text{Number of drops}} = \frac{2.5 \, \text{cm}^3}{100} = 0.025 \, \text{cm}^3 \text{ per drop}
\][/tex]
ii. What is the reading of the burette if 300 drops are allowed to fall?
We already know the average volume of one drop is 0.025 cm³. To find the total volume for 300 drops:
[tex]\[
\text{Total volume for 300 drops} = \text{Number of drops} \times \text{Average volume per drop} = 300 \times 0.025 \, \text{cm}^3 = 7.5 \, \text{cm}^3
\][/tex]
To determine the new burette reading, we add this total volume to the initial reading:
[tex]\[
\text{New burette reading} = \text{Initial reading} + \text{Total volume for 300 drops} = 39.0 \, \text{cm}^3 + 7.5 \, \text{cm}^3 = 46.5 \, \text{cm}^3
\][/tex]
Determine the density of the mixture.
In order to determine the density of the mixture, additional information such as the mass of the water or the components of the mixture would be required. Since no such information is given, it's not possible to determine the density based on the provided data. Thus, we cannot calculate the density of the mixture with the information at hand.
