Answer :
To find the slope of the line passing through the points [tex]\((5, 2)\)[/tex] and [tex]\((8, 7)\)[/tex], we will use the slope formula:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
where [tex]\((x_1, y_1)\)[/tex] is the first point and [tex]\((x_2, y_2)\)[/tex] is the second point.
Given the points [tex]\((5, 2)\)[/tex] and [tex]\((8, 7)\)[/tex]:
[tex]\[ (x_1, y_1) = (5, 2) \\ (x_2, y_2) = (8, 7) \][/tex]
Substitute these values into the slope formula:
[tex]\[ m = \frac{7 - 2}{8 - 5} \][/tex]
Simplify the numerator and the denominator:
[tex]\[ m = \frac{5}{3} \][/tex]
So, the slope of the line is:
[tex]\[ m = \frac{5}{3} \][/tex]
Therefore, the correct choice is:
[tex]\[ \boxed{\frac{5}{3}} \][/tex]
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
where [tex]\((x_1, y_1)\)[/tex] is the first point and [tex]\((x_2, y_2)\)[/tex] is the second point.
Given the points [tex]\((5, 2)\)[/tex] and [tex]\((8, 7)\)[/tex]:
[tex]\[ (x_1, y_1) = (5, 2) \\ (x_2, y_2) = (8, 7) \][/tex]
Substitute these values into the slope formula:
[tex]\[ m = \frac{7 - 2}{8 - 5} \][/tex]
Simplify the numerator and the denominator:
[tex]\[ m = \frac{5}{3} \][/tex]
So, the slope of the line is:
[tex]\[ m = \frac{5}{3} \][/tex]
Therefore, the correct choice is:
[tex]\[ \boxed{\frac{5}{3}} \][/tex]