Nolan used the following procedure to find an estimate for [tex]\sqrt{18}[/tex].

Step 1: Since [tex]4^2=16[/tex] and [tex]5^2=25[/tex] and [tex]16\ \textless \ 18\ \textless \ 25[/tex], [tex]\sqrt{18}[/tex] is between 4 and 5.

Step 2: Since 18 is closer to 16, square the tenths closer to 4.
[tex]\[
\begin{array}{l}
4.1^2=16.81 \\
4.2^2=17.64 \\
4.3^2=18.49 \\
4.4^2=19.36
\end{array}
\][/tex]

Step 3: Since 18.49 rounds to 18, [tex]4.3[/tex] is the best approximation for [tex]\sqrt{18}[/tex].

In which step, if any, did Nolan make an error?

A. In step 1, [tex]\sqrt{18}[/tex] is between 4 and 5 because [tex]\sqrt{18} \approx 20[/tex] and [tex]4 \times 5=20[/tex].

B. In step 2, he made a calculation error when squaring.

C. In step 3, he should have determined which square is closest to 18.

D. Nolan did not make an error.



Answer :

Let’s look at the steps Nolan took and verify their correctness.

### Step 1
Nolan correctly identified that since [tex]\(4^2 = 16\)[/tex] and [tex]\(5^2 = 25\)[/tex], and because [tex]\(16 < 18 < 25\)[/tex], [tex]\(\sqrt{18}\)[/tex] must lie between 4 and 5. This step is accurate.

### Step 2
Nolan performed calculations to square numbers that are in the range from 4.1 to 4.4:

[tex]\[ \begin{align*} 4.1^2 &= 16.81 \\ 4.2^2 &= 17.64 \\ 4.3^2 &= 18.49 \\ 4.4^2 &= 19.36 \end{align*} \][/tex]

These calculations are correct.

### Step 3
In step 3, Nolan concluded that [tex]\(4.3^2 = 18.49\)[/tex] rounds to 18, making 4.3 the best approximation for [tex]\(\sqrt{18}\)[/tex]. However, this step needs closer inspection to check for accuracy in approximation:

The actual result of the calculations are:
[tex]\[ \begin{align*} 4.1^2 &= 16.81 \\ 4.2^2 &= 17.64 \\ 4.3^2 &= 18.49 \\ 4.4^2 &= 19.36 \end{align*} \][/tex]

By evaluating these results:
- [tex]\(16.81\)[/tex] is less than 18.
- [tex]\(17.64\)[/tex] is less than 18.
- [tex]\(18.49\)[/tex] is greater than 18.
- [tex]\(19.36\)[/tex] is greater than 18.

Since [tex]\(18.49\)[/tex] is greater than 18, we note that [tex]\(4.2^2 = 17.64\)[/tex] is actually closer to 18 than [tex]\(4.3^2 = 18.49\)[/tex]. Thus, the error is in determining the closest value. Nolan should have identified that [tex]\(17.64\)[/tex] (from [tex]\(4.2^2\)[/tex]) is closer to 18 than [tex]\(18.49\)[/tex] (from [tex]\(4.3^2\)[/tex]).

Therefore, the error occurred in Step 3, where Nolan should have determined that [tex]\( \sqrt{18} \)[/tex] is best approximated by 4.2, not 4.3.