Answer :
To solve this problem, let's walk through each experiment and predict the observable outcomes based on the given conditions.
### Experiment 1:
Scenario:
- A student observes tiny bubbles clinging to the inside of an unopened plastic bottle full of carbonated soft drink.
- The student then squeezes the bottle.
Possible Predictions:
1. The bubbles will shrink, and some may vanish.
2. The bubbles will grow, and more may appear.
3. The bubbles won't change.
4. I need more information to predict what will happen to the bubbles.
Predicted Observation:
When the bottle is squeezed, the pressure inside the bottle increases. By increasing the pressure, the solubility of the gas in the liquid increases, which causes the gas bubbles to shrink or dissolve back into the liquid. Therefore, the correct prediction is:
- The bubbles will shrink, and some may vanish.
### Experiment 2:
Scenario:
- A student has two unopened 33 cL cans containing carbonated water.
- Can A has been stored in the garage at [tex]\(32^{\circ} C\)[/tex].
- Can B has been stored in the fridge at [tex]\(8^{\circ} C\)[/tex].
- The student opens one can at a time, and both cans make a fizzing sound.
Possible Predictions:
1. Can A will make a louder and stronger fizz than Can B.
2. Can B will make a louder and stronger fizz than Can A.
3. The fizz will be the same for both cans.
4. There is not enough information to predict which can will make the louder fizz.
Predicted Observation:
Temperature affects the solubility of gases in liquids. Gases are less soluble in liquids at higher temperatures. Hence, the gas in Can A (stored at [tex]\(32^{\circ} C\)[/tex]) is less soluble than the gas in Can B (stored at [tex]\(8^{\circ} C\)[/tex]). Therefore, upon opening, Can A will release more gas rapidly, creating a louder and stronger fizz than Can B. Thus, the correct prediction is:
- Can A will make a louder and stronger fizz than Can B.
### Final Answer:
[tex]\[ \begin{array}{|c|c|} \hline \text{experiment} & \text{predicted observation} \\ \hline \begin{array}{l} \text{A student sees tiny bubbles clinging to the inside of an} \\ \text{unopened plastic bottle full of carbonated soft drink. The} \\ \text{student squeezes the bottle.} \end{array} & \begin{array}{l} \text{The bubbles will shrink, and some may vanish.} \end{array} \\ \hline \begin{array}{l} \text{A student has two unopened 33 cL cans containing } \\ \text{carbonated water. Can } A \text{ has been stored in the garage } \\ (32^{\circ} C) \text{ and can B has been stored in the fridge } \\ (8^{\circ} C). \text{ The student opens one can at a time, both } \\ \text{cans make a fizz.} \end{array} & \begin{array}{l} \text{Can A will make a louder and stronger fizz than can B.} \end{array} \\ \hline \end{array} \][/tex]
### Experiment 1:
Scenario:
- A student observes tiny bubbles clinging to the inside of an unopened plastic bottle full of carbonated soft drink.
- The student then squeezes the bottle.
Possible Predictions:
1. The bubbles will shrink, and some may vanish.
2. The bubbles will grow, and more may appear.
3. The bubbles won't change.
4. I need more information to predict what will happen to the bubbles.
Predicted Observation:
When the bottle is squeezed, the pressure inside the bottle increases. By increasing the pressure, the solubility of the gas in the liquid increases, which causes the gas bubbles to shrink or dissolve back into the liquid. Therefore, the correct prediction is:
- The bubbles will shrink, and some may vanish.
### Experiment 2:
Scenario:
- A student has two unopened 33 cL cans containing carbonated water.
- Can A has been stored in the garage at [tex]\(32^{\circ} C\)[/tex].
- Can B has been stored in the fridge at [tex]\(8^{\circ} C\)[/tex].
- The student opens one can at a time, and both cans make a fizzing sound.
Possible Predictions:
1. Can A will make a louder and stronger fizz than Can B.
2. Can B will make a louder and stronger fizz than Can A.
3. The fizz will be the same for both cans.
4. There is not enough information to predict which can will make the louder fizz.
Predicted Observation:
Temperature affects the solubility of gases in liquids. Gases are less soluble in liquids at higher temperatures. Hence, the gas in Can A (stored at [tex]\(32^{\circ} C\)[/tex]) is less soluble than the gas in Can B (stored at [tex]\(8^{\circ} C\)[/tex]). Therefore, upon opening, Can A will release more gas rapidly, creating a louder and stronger fizz than Can B. Thus, the correct prediction is:
- Can A will make a louder and stronger fizz than Can B.
### Final Answer:
[tex]\[ \begin{array}{|c|c|} \hline \text{experiment} & \text{predicted observation} \\ \hline \begin{array}{l} \text{A student sees tiny bubbles clinging to the inside of an} \\ \text{unopened plastic bottle full of carbonated soft drink. The} \\ \text{student squeezes the bottle.} \end{array} & \begin{array}{l} \text{The bubbles will shrink, and some may vanish.} \end{array} \\ \hline \begin{array}{l} \text{A student has two unopened 33 cL cans containing } \\ \text{carbonated water. Can } A \text{ has been stored in the garage } \\ (32^{\circ} C) \text{ and can B has been stored in the fridge } \\ (8^{\circ} C). \text{ The student opens one can at a time, both } \\ \text{cans make a fizz.} \end{array} & \begin{array}{l} \text{Can A will make a louder and stronger fizz than can B.} \end{array} \\ \hline \end{array} \][/tex]