Answer :
Answer:
Explanation:
Calculate the effective resistance of a pocket calculator that has a 1.35-V battery and through which 2x10⁻⁴ A flowsSolve ForKnown 1 Identify knowns & unknowns This question is asking to find resistance with knowns of voltage and current. 2 Identify the related formula This is the formula used for problems related to Ohm's law. \(\xpmhighlightbox{bgcolor=#F3E8FD, underlinecolor=#6232EC}{V}\,=\xpmhighlightbox{bgcolor=#F3E8FD, underlinecolor=#6232EC}{I}\,\xpmhighlightbox{bgcolor=#D8F8FF, underlinecolor=#00758C, linestyle=dashed}{R}\,\) \(V\) = voltage \(I\) = current \(R\) = resistance 3 Input variables, solve and simplify Identify knowns\(V=1.35~\textrm{V}\\ I=2~\textrm{A}\)Plug-in values\(1.35~\textrm{V}=2~\textrm{A}\cdot R\) Divide both sides by the same factor \(\frac{1.35~\textrm{V}}{\mathbfit{2~}\textrm{A}}=\frac{2~\textrm{A}\cdot R}{\mathbfit{2~}\textrm{A}}\) Simplify \(R=0.675~\textrm{V}/\textrm{A}\)Convert units\(R=0.675~\textrm{\Omega }\) 4 Check unit of measurement resistance is measured in ohms. Solution \(R=0.675~\textrm{\Omega }\)
