Which of the following is an equivalent expression for [tex]$r$[/tex] in terms of [tex]$S$[/tex] and [tex][tex]$t$[/tex][/tex] whenever [tex]$r, S,$[/tex] and [tex]$t$[/tex] are all distinct and [tex]$S = \frac{r t - 3}{r - t}$[/tex]?

A. [tex]\frac{S t - 3}{S - t}[/tex]
B. [tex]\frac{S - 3}{S - 1}[/tex]
C. [tex]\frac{S - t}{S - 3}[/tex]
D. [tex]\frac{S t - 3}{S + t}[/tex]
E. [tex]\frac{3}{t - S}[/tex]



Answer :

To determine which of the following expressions is equivalent to [tex]\( r \)[/tex] in terms of [tex]\( S \)[/tex] and [tex]\( t \)[/tex] when [tex]\( S = \frac{r t - 3}{r - t} \)[/tex], we need to manipulate the initial equation to solve for [tex]\( r \)[/tex].

Given the equation:

[tex]\[ S = \frac{r t - 3}{r - t} \][/tex]

Our goal is to isolate [tex]\( r \)[/tex]. Let's proceed step-by-step:

1. Multiply both sides by [tex]\( r - t \)[/tex] to clear the denominator:

[tex]\[ S (r - t) = r t - 3 \][/tex]

2. Expand the left side of the equation:

[tex]\[ S r - S t = r t - 3 \][/tex]

3. Rearrange the terms to isolate those involving [tex]\( r \)[/tex] on one side:

[tex]\[ S r - r t = S t - 3 \][/tex]

4. Factor out [tex]\( r \)[/tex] on the left side:

[tex]\[ r (S - t) = S t - 3 \][/tex]

5. Solve for [tex]\( r \)[/tex] by dividing both sides of the equation by [tex]\( (S - t) \)[/tex]:

[tex]\[ r = \frac{S t - 3}{S - t} \][/tex]

Thus, the expression for [tex]\( r \)[/tex] in terms of [tex]\( S \)[/tex] and [tex]\( t \)[/tex] is:

[tex]\[ r = \frac{S t - 3}{S - t} \][/tex]

Now, we can compare this result to the given answer choices:

A. [tex]\( \frac{S t - 3}{S - t} \)[/tex]

B. [tex]\( \frac{S - 3}{S - 1} \)[/tex]

C. [tex]\( \frac{S - t}{S - 3} \)[/tex]

D. [tex]\( \frac{S t - 3}{S + t} \)[/tex]

E. [tex]\( \frac{3}{t - S} \)[/tex]

The correct equivalent expression for [tex]\( r \)[/tex] in terms of [tex]\( S \)[/tex] and [tex]\( t \)[/tex] is:

[tex]\[ \boxed{\frac{S t - 3}{S - t}} \][/tex]

So, the correct answer is [tex]\( \boxed{A} \)[/tex].