A thunderclap sends a sound wave through the air and the ocean below. The thunderclap sound wave has a constant frequency of 100 Hz. What is the wavelength of the sound wave in water? (The equation for the speed of a wave is [tex]$v=f \times \lambda$[/tex].)

\begin{tabular}{|l|c|c|c|c|}
\hline
& Water & Diamond & Glass & Air \\
\hline
\begin{tabular}{l}
Speed of \\
sound \\
[tex]$(m/s)$[/tex]
\end{tabular} & 1,493 & 12,000 & 5,640 & 346 \\
\hline
\end{tabular}

A. 3.46 m
B. 11.00 m
C. 12.00 m
D. 14.93 m



Answer :

To solve this problem, we need to determine the wavelength of the sound wave in water. The formula given for the speed of a wave is:

[tex]\[ v = f \times \lambda \][/tex]

where:
- [tex]\( v \)[/tex] is the speed of the sound wave,
- [tex]\( f \)[/tex] is the frequency of the sound wave,
- [tex]\( \lambda \)[/tex] is the wavelength of the sound wave.

We can solve for the wavelength [tex]\( \lambda \)[/tex]:

[tex]\[ \lambda = \frac{v}{f} \][/tex]

The problem provides the following information:
- The frequency of the sound wave [tex]\( f = 100 \, \text{Hz} \)[/tex],
- The speed of sound in water [tex]\( v = 1,493 \, \text{m/s} \)[/tex].

Substituting these values into the formula:

[tex]\[ \lambda = \frac{1,493 \, \text{m/s}}{100 \, \text{Hz}} \][/tex]

Perform the division:

[tex]\[ \lambda = 14.93 \, \text{m} \][/tex]

Therefore, the wavelength of the sound wave in water is 14.93 meters.

So, the correct answer is:

D. 14.93 m

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