trinitygoitseone
Answered

Use the table below to fill in the data collected during the investigation and the calculated values.

[tex]\[
\begin{array}{|c|c|c|}
\hline
Galvanic Cell & \text{Standard Cell Potential (V)} & \text{Experimental Value} \\
\hline
\text{Description} & E_{\text{cell}} = E_{\text{cathode}} - E_{\text{anode}} & \text{Value} \\
\hline
Fe - Cu & 0.54 + 0.44 = 0.98 & \text{Value} \\
\hline
\end{array}
\][/tex]

Please use the table format to organize your data accurately.



Answer :

GinnyAnswer
Certainly! Let's format the table with the collected data and the calculated values as specified. I'll ensure the table is clear and fully populated.

```
\begin{tabular}{|c|c|c|}
\hline
Galvanic Cell & Standard Cell Potential (V) & Experimental Value \\
\hline
[tex]$Fe - Cu$[/tex] & [tex]$0.98$[/tex] & \\
\hline
\end{tabular}
```

Here is a step-by-step breakdown for clarity:

1. Identify the components of the galvanic cell: In this case, the cell is composed of iron (Fe) and copper (Cu).
2. Calculate the standard cell potential: The standard cell potential for the Fe - Cu cell is given as:

[tex]\[ 0.54 + 0.44 = 0.98 \text{ V} \][/tex]

3. Enter the values into the table in their respective columns:
- The "Galvanic Cell" column receives the cell identification: [tex]\( Fe - Cu \)[/tex].
- The "Standard Cell Potential (V)" column receives the calculated potential (0.98 V).
- The "Experimental Value" column is left empty, as no experimental value is provided in the question prompt.

So, the completed table will look as follows:

```
\begin{tabular}{|c|c|c|}
\hline
Galvanic Cell & Standard Cell Potential (V) & Experimental Value \\
\hline
[tex]$Fe - Cu$[/tex] & [tex]$0.98$[/tex] & \\
\hline
\end{tabular}
```

This step-by-step solution fills the required table with the data given and the calculated values.

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