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A jet airplane reaches [tex]$809 \, \text{km/h}$[/tex] on a certain flight. How long does it take to cover [tex]$249 \, \text{m}$[/tex]?

Set up the math expression, but don't solve it. Ensure your answer includes all the correct unit symbols.

[tex]\[
\text{time} = \frac{249 \, \text{m}}{809 \, \text{km/h}} \times \frac{1 \, \text{km}}{1000 \, \text{m}}
\][/tex]



Answer :

GinnyAnswer
Certainly! Let's set up the math expressions to solve the given problem step-by-step.

1. Convert the speed from km/h to m/s:

We know that:
- 1 kilometer (km) = 1000 meters (m)
- 1 hour (h) = 3600 seconds (s)

Consequently:
[tex]\[ \text{Speed in m/s} = 809 \ \text{km/h} \times \frac{1000 \ \text{m}}{1 \ \text{km}} \times \frac{1 \ \text{h}}{3600 \ \text{s}} \][/tex]

2. Express the distance to be covered:

The distance is given directly as:
[tex]\[ \text{Distance} = 249 \ \text{m} \][/tex]

3. Calculate the time required to cover the distance:

Time is given by:
[tex]\[ \text{Time} = \frac{\text{Distance}}{\text{Speed in m/s}} \][/tex]

Bringing it all together:

Time [tex]\( t \)[/tex] required to cover 249 meters at 809 km/h in seconds is:
[tex]\[ t \ (\text{seconds}) = \frac{249 \ \text{m}}{809 \ \text{km/h} \times \frac{1000 \ \text{m}}{1 \ \text{km}} \times \frac{1 \ \text{h}}{3600 \ \text{s}}} \][/tex]

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