A chemist makes 0.910 L of mercury(II) iodide [tex]\left( \text{HgI}_2 \right)[/tex] working solution by adding distilled water to 0.100 L of a [tex]0.0000382 \frac{\text{mol}}{\text{L}}[/tex] stock solution of mercury(II) iodide in water.

Calculate the concentration of the chemist's working solution. Be sure your answer has the correct number of significant digits. [tex]\square[/tex]



Answer :

To calculate the concentration of the working solution, we need to follow a series of steps to determine how the concentration changes when the stock solution is diluted. Here is a detailed, step-by-step solution:

1. Determine the amount of solute in the stock solution:

- The volume of the stock solution is [tex]\(0.100 \, \text{L}\)[/tex].
- The concentration of the stock solution is [tex]\(0.0000382 \, \frac{\text{mol}}{\text{L}}\)[/tex].

The amount of solute (in moles) in the stock solution can be calculated using the formula:
[tex]\[ \text{Amount of solute} = \text{Volume of stock solution} \times \text{Concentration of stock solution} \][/tex]
Substituting in the given values:
[tex]\[ \text{Amount of solute} = 0.100 \, \text{L} \times 0.0000382 \, \frac{\text{mol}}{\text{L}} = 3.82 \times 10^{-6} \, \text{mol} \][/tex]

2. Calculate the concentration of the working solution:

- The total volume of the working solution is [tex]\(0.910 \, \text{L}\)[/tex].
- The amount of solute remains constant during dilution (it is the same as calculated above).

The concentration of the working solution can be determined using the formula:
[tex]\[ \text{Concentration of working solution} = \frac{\text{Amount of solute}}{\text{Volume of working solution}} \][/tex]
Substituting the values:
[tex]\[ \text{Concentration of working solution} = \frac{3.82 \times 10^{-6} \, \text{mol}}{0.910 \, \text{L}} = 4.197802197802198 \times 10^{-6} \, \frac{\text{mol}}{\text{L}} \][/tex]

3. Express the final concentration with the correct number of significant digits:

- The initial concentration [tex]\(0.0000382 \, \frac{\text{mol}}{\text{L}}\)[/tex] has 3 significant digits.
- The volume measurements (0.100 L and 0.910 L) each have 3 significant digits.

Therefore, the final concentration should also be expressed with 3 significant digits:
[tex]\[ \text{Concentration of working solution} = 4.20 \times 10^{-6} \, \frac{\text{mol}}{\text{L}} \][/tex]

Thus, the concentration of the chemist's working solution is [tex]\( \boxed{4.20 \times 10^{-6} \, \frac{\text{mol}}{\text{L}}} \)[/tex].