To determine the amount of carbon monoxide (CO) produced by the combustion of 3.2 grams of JeHu, follow these steps:
1. Determine the number of moles of JeHu:
First, we need to find out how many moles of JeHu are contained in 3.2 grams. The molar mass of JeHu is given as 832 grams per mole. The formula to calculate the number of moles is:
[tex]\[
\text{moles of JeHu} = \frac{\text{mass of JeHu}}{\text{molar mass of JeHu}}
\][/tex]
Plugging in the given values:
[tex]\[
\text{moles of JeHu} = \frac{3.2 \text{ grams}}{832 \text{ grams per mole}} = 0.0038461538461538464 \text{ moles}
\][/tex]
2. Determine the moles of CO produced:
According to the given reaction, which is simplified for the purpose of this problem, each mole of JeHu produces 8 moles of CO. Therefore, we calculate the moles of CO by multiplying the moles of JeHu by the number of moles of CO produced per mole of JeHu.
[tex]\[
\text{moles of CO produced} = \text{moles of JeHu} \times 8
\][/tex]
Plugging in the moles of JeHu calculated earlier:
[tex]\[
\text{moles of CO produced} = 0.0038461538461538464 \times 8 = 0.03076923076923077 \text{ moles}
\][/tex]
Therefore, when 3.2 grams of JeHu undergoes combustion, it produces 0.03076923076923077 moles of carbon monoxide (CO).
