A bag contains only red marbles, blue marbles, and yellow marbles. The probability of picking a red marble is [tex]\frac{2}{5}[/tex]. There are nine yellow marbles. The probability of picking a blue marble is three times as likely as picking a yellow marble.

Work out the total number of marbles in the bag. You must show your working.



Answer :

To determine the total number of marbles in the bag, let's start by defining and working with the given probabilities and known quantities:

1. Probability of Red Marble: The probability of picking a red marble is given as [tex]\(\frac{2}{5}\)[/tex].

2. Number of Yellow Marbles: There are 9 yellow marbles in the bag.

3. Probability of Blue Marble: The probability of picking a blue marble is three times the probability of picking a yellow marble.

Let the total number of marbles in the bag be [tex]\(T\)[/tex].

Step-by-Step Solution:

1. Probability of Picking a Yellow Marble:

Since there are 9 yellow marbles out of a total of [tex]\(T\)[/tex] marbles, the probability of picking a yellow marble is:
[tex]\[ P(Y) = \frac{9}{T} \][/tex]

2. Probability of Picking a Blue Marble:

Given that the probability of picking a blue marble is three times the probability of picking a yellow marble, we have:
[tex]\[ P(B) = 3 \times P(Y) = 3 \times \frac{9}{T} = \frac{27}{T} \][/tex]

3. Sum of All Probabilities:

The sum of the probabilities of picking either a red, blue, or yellow marble must equal 1 (since one of these outcomes must happen when a marble is picked). Therefore, we can write:
[tex]\[ P(R) + P(Y) + P(B) = 1 \][/tex]
Substituting the known probabilities:
[tex]\[ \frac{2}{5} + \frac{9}{T} + \frac{27}{T} = 1 \][/tex]

4. Combine Like Terms:

Combine the terms involving [tex]\(T\)[/tex]:
[tex]\[ \frac{2}{5} + \frac{9 + 27}{T} = 1 \][/tex]
Simplify the fraction:
[tex]\[ \frac{2}{5} + \frac{36}{T} = 1 \][/tex]

5. Isolate and Solve for [tex]\(T\)[/tex]:

To isolate [tex]\(T\)[/tex], we need to clear the fraction. First, subtract [tex]\(\frac{2}{5}\)[/tex] from both sides:
[tex]\[ \frac{36}{T} = 1 - \frac{2}{5} \][/tex]
Simplify the right-hand side:
[tex]\[ 1 - \frac{2}{5} = \frac{5}{5} - \frac{2}{5} = \frac{3}{5} \][/tex]
So we have:
[tex]\[ \frac{36}{T} = \frac{3}{5} \][/tex]

6. Cross Multiply to Solve for [tex]\(T\)[/tex]:

Cross-multiply to clear the fractions:
[tex]\[ 36 \times 5 = 3 \times T \][/tex]
Simplify:
[tex]\[ 180 = 3T \][/tex]
Divide both sides by 3:
[tex]\[ T = \frac{180}{3} = 60 \][/tex]

Therefore, the total number of marbles in the bag is:
[tex]\[ T = 60 \][/tex]

So, the total number of marbles in the bag is 60.