Point [tex]\( B(5, -2) \)[/tex] is translated 4 units right and 2 units down and then dilated by a factor of 2 using the origin as the center of dilation. What is the resultant point?

A. [tex]\( B^{\prime}(18, -8) \)[/tex]
B. [tex]\( B^{\prime \prime}(10, -4) \)[/tex]
C. [tex]\( B^{\prime}(2, 0) \)[/tex]
D. [tex]\( B^*(8, -4) \)[/tex]



Answer :

To solve this problem, we'll follow the steps of translation and dilation as described:

1. Initial Position:
[tex]\[ B (5, -2) \][/tex]

2. Translation:
We translate the point 4 units to the right and 2 units down.

- Translating 4 units to the right involves adding 4 to the x-coordinate:
[tex]\[ x_{\text{translated}} = 5 + 4 = 9 \][/tex]

- Translating 2 units down involves subtracting 2 from the y-coordinate:
[tex]\[ y_{\text{translated}} = -2 - 2 = -4 \][/tex]

The new coordinates after translation are:
[tex]\[ (9, -4) \][/tex]

3. Dilation:
We now dilate this translated point by a factor of 2 using the origin as the center (origin (0,0)).

- To dilate by a factor of 2, we multiply both coordinates of the translated point by 2:
[tex]\[ x_{\text{dilated}} = 9 \times 2 = 18 \][/tex]
[tex]\[ y_{\text{dilated}} = -4 \times 2 = -8 \][/tex]

The resultant coordinates after dilation are:
[tex]\[ (18, -8) \][/tex]

Thus, the resulting point after the translation and dilation operations is:
[tex]\[ \boxed{(18,-8)} \][/tex]

From the given options, the correct answer is:
[tex]\[ A. \quad B^{\prime}(18,-8) \][/tex]