Answer:
D: Y'(4, -1)
Step-by-step explanation:
When a point is reflected across a horizontal line, the x-coordinate of the point remains unchanged, but the y-coordinate is adjusted based on its distance from the horizontal line.
In this case, we are reflecting point Y(4, 3) across the line y = 1, so the x-coordinate of the reflected point Y′ remains x = 4.
The y-coordinate of point Y is y = 3, so the vertical distance from Y to the line y = 1 is 2 units. The reflected point will be the same distance on the opposite side of the line. Since the reflected point is below the line, we subtract 2 from the y-coordinate of Y. Therefore, the y-coordinate of Y′ is 1 - 2 = -1.
So, the coordinates of Y' after a reflection across y = 1 are:
[tex]\LARGE\boxed{Y'(4,-1)}[/tex]
