Rewrite in simplest radical form [tex]\frac{1}{x^{-\frac{3}{6}}}[/tex]. Show each step of your process.

1. Start with the original expression:
[tex]\frac{1}{x^{-\frac{3}{6}}}[/tex]

2. Simplify the exponent:
[tex]\frac{1}{x^{-\frac{1}{2}}}[/tex]

3. Use the property of negative exponents:
[tex]x^{\frac{1}{2}}[/tex]

4. Rewrite in radical form:
[tex]\sqrt{x}[/tex]

So, the simplest radical form of [tex]\frac{1}{x^{-\frac{3}{6}}}[/tex] is [tex]\sqrt{x}[/tex].



Answer :

Sure! Let's simplify the expression [tex]\(\frac{1}{x^{-\frac{3}{6}}}\)[/tex] step-by-step.

1. Simplify the exponent: The exponent [tex]\(-\frac{3}{6}\)[/tex] can be simplified. Since [tex]\(\frac{3}{6} = \frac{1}{2}\)[/tex], the expression becomes:
[tex]\[ -\frac{3}{6} = -\frac{1}{2} \][/tex]
Therefore, [tex]\(\frac{1}{x^{-\frac{3}{6}}}\)[/tex] can be rewritten as:
[tex]\[ \frac{1}{x^{-\frac{1}{2}}} \][/tex]

2. Apply the negative exponent property: The property of exponents states that [tex]\(a^{-b} = \frac{1}{a^b}\)[/tex]. Applying this property to the expression [tex]\(x^{-\frac{1}{2}}\)[/tex], we get:
[tex]\[ x^{-\frac{1}{2}} = \frac{1}{x^{\frac{1}{2}}} \][/tex]

3. Rewrite the initial expression: Using the result from the previous step in our original expression:
[tex]\[ \frac{1}{x^{-\frac{1}{2}}} = x^{\frac{1}{2}} \][/tex]

4. Express as a radical: The exponent [tex]\(\frac{1}{2}\)[/tex] can be expressed in radical form as the square root. Therefore:
[tex]\[ x^{\frac{1}{2}} = \sqrt{x} \][/tex]

So, [tex]\(\frac{1}{x^{-\frac{3}{6}}}\)[/tex] rewritten in the simplest radical form is:
[tex]\[ \sqrt{x} \][/tex]