Matt and Linda each start the year with 15 vacation days. The table below shows how many vacation days each of them had left at the end of each quarter.

\begin{tabular}{|c|c|c|c|c|}
\hline
& Jan. - Mar. & Apr. - June & July - Sept. & Oct. - Dec. \\
\hline
Matt & 13 & 11 & 7 & 4 \\
\hline
Linda & 12 & 11 & 7 & 0 \\
\hline
\end{tabular}

Which statement is true?

A. Both the mean and the median number of vacation days Matt has remaining are greater than the mean and the median number of vacation days Linda has remaining.

B. The median number of vacation days Matt has remaining is less than the median number of vacation days Linda has remaining.

C. The median number of vacation days Linda has remaining is less than the median number of vacation days Matt has remaining.

D. The mean number of vacation days Matt has remaining is greater than the mean number of vacation days Linda has remaining.



Answer :

To determine which statement is true regarding the remaining vacation days for Matt and Linda, we will calculate the mean and median values for both of them.

### Step-by-Step Calculation:

#### 1. Data for Matt and Linda:
- Matt's vacation days at the end of each quarter: [13, 11, 7, 4]
- Linda's vacation days at the end of each quarter: [12, 11, 7, 0]

#### 2. Calculate the Mean:

- Mean for Matt:
[tex]\[ \text{mean}_{\text{Matt}} = \frac{13 + 11 + 7 + 4}{4} \][/tex]
Simplifying the numerator:
[tex]\[ 13 + 11 = 24 \][/tex]
[tex]\[ 24 + 7 = 31 \][/tex]
[tex]\[ 31 + 4 = 35 \][/tex]
Therefore,
[tex]\[ \text{mean}_{\text{Matt}} = \frac{35}{4} = 8.75 \][/tex]

- Mean for Linda:
[tex]\[ \text{mean}_{\text{Linda}} = \frac{12 + 11 + 7 + 0}{4} \][/tex]
Simplifying the numerator:
[tex]\[ 12 + 11 = 23 \][/tex]
[tex]\[ 23 + 7 = 30 \][/tex]
[tex]\[ 30 + 0 = 30 \][/tex]
Therefore,
[tex]\[ \text{mean}_{\text{Linda}} = \frac{30}{4} = 7.5 \][/tex]

#### 3. Calculate the Median:

- Median for Matt:
The ordered list of Matt’s vacation days is [4, 7, 11, 13]. The median is the average of the two middle numbers:
[tex]\[ \text{median}_{\text{Matt}} = \frac{7 + 11}{2} = \frac{18}{2} = 9.0 \][/tex]

- Median for Linda:
The ordered list of Linda’s vacation days is [0, 7, 11, 12]. The median is the average of the two middle numbers:
[tex]\[ \text{median}_{\text{Linda}} = \frac{7 + 11}{2} = \frac{18}{2} = 9.0 \][/tex]

### Comparison and Conclusion:

- Mean Comparison:
[tex]\[ \text{mean}_{\text{Matt}} = 8.75 > 7.5 = \text{mean}_{\text{Linda}} \][/tex]

- Median Comparison:
[tex]\[ \text{median}_{\text{Matt}} = 9.0 = 9.0 = \text{median}_{\text{Linda}} \][/tex]

Given these calculations, we can confirm that:
- The mean number of vacation days Matt has remaining is greater than the mean number of vacation days Linda has remaining.
- The median number of vacation days remaining for both Matt and Linda is the same.

Thus, the correct statement is:
D. The mean number of vacation days Matt has remaining is greater than the mean number of vacation days Linda has remaining.