2. A model of a shed measures [tex]\({1 \frac{3}{4}}\)[/tex] feet long by [tex]\({1 \frac{1}{2}}\)[/tex] feet tall by [tex]\({1 \frac{1}{4}}\)[/tex] feet wide. The actual shed has a scale factor of 6 times the model. What are the dimensions of the shed?

A. [tex]\({11 \frac{1}{2}}\)[/tex] feet by 9 feet by [tex]\({6 \frac{1}{4}}\)[/tex] feet
B. [tex]\({10 \frac{1}{2}}\)[/tex] feet by 9 feet by [tex]\({7 \frac{1}{2}}\)[/tex] feet
C. [tex]\({10 \frac{1}{2}}\)[/tex] feet by [tex]\({8 \frac{1}{2}}\)[/tex] feet by [tex]\({7 \frac{1}{4}}\)[/tex]
D. [tex]\({6 \frac{3}{4}}\)[/tex] feet by [tex]\({6 \frac{1}{2}}\)[/tex] feet by [tex]\({6 \frac{1}{4}}\)[/tex]



Answer :

To solve this problem, we will determine the actual dimensions of the shed by using the given model dimensions and applying the scale factor.

The model dimensions are:
- Length: [tex]\(1 \frac{3}{4}\)[/tex] feet
- Height: [tex]\(1 \frac{1}{2}\)[/tex] feet
- Width: [tex]\(1 \frac{1}{4}\)[/tex] feet

The scale factor is 6, which means the actual shed is six times larger than the model.

1. Length Calculation:
- Model length = [tex]\(1 \frac{3}{4}\)[/tex] feet
- Converting the mixed number to an improper fraction: [tex]\(1 \frac{3}{4} = \frac{7}{4}\)[/tex] feet
- Actual length = [tex]\(\frac{7}{4} \times 6 = \frac{42}{4} = 10.5\)[/tex] feet

2. Height Calculation:
- Model height = [tex]\(1 \frac{1}{2}\)[/tex] feet
- Converting the mixed number to an improper fraction: [tex]\(1 \frac{1}{2} = \frac{3}{2}\)[/tex] feet
- Actual height = [tex]\(\frac{3}{2} \times 6 = \frac{18}{2} = 9\)[/tex] feet

3. Width Calculation:
- Model width = [tex]\(1 \frac{1}{4}\)[/tex] feet
- Converting the mixed number to an improper fraction: [tex]\(1 \frac{1}{4} = \frac{5}{4}\)[/tex] feet
- Actual width = [tex]\(\frac{5}{4} \times 6 = \frac{30}{4} = 7.5\)[/tex] feet

Therefore, the dimensions of the actual shed are:

- Length: 10.5 feet
- Height: 9 feet
- Width: 7.5 feet

Among the given options, the correct dimensions that match our calculated results are:

[tex]\(10 \frac{1}{2}\)[/tex] feet by 9 feet by [tex]\(7 \frac{1}{2}\)[/tex] feet.

Thus, the correct option is:
[tex]\( \boxed{10 \frac{1}{2}} \text{ feet by 9 feet by } 7 \frac{1}{2} \text{ feet}\)[/tex]