For \#1 - 6, determine if the system has one solution, no solution, or infinitely many solutions. If there is one solution, identify the ordered pair [tex]\((x, y)\)[/tex].

1.
[tex]\[
\begin{cases}
y = -\frac{5}{3}x + 3 \\
y = \frac{1}{3}x - 3
\end{cases}
\][/tex]



Answer :

Certainly! Let's solve the system of equations step-by-step to determine if it has one solution, no solution, or infinitely many solutions. If there is one solution, we will identify the ordered pair [tex]\((x, y)\)[/tex].

The given system of equations is:
[tex]\[ \left\{\begin{array}{l} y = -\frac{5}{3} x + 3 \\ y = \frac{1}{3} x - 3 \end{array}\right. \][/tex]

### Step 1: Set the Equations Equal to Each Other

Since both equations are equal to [tex]\(y\)[/tex], we can set the right-hand sides of the equations equal to each other:
[tex]\[ -\frac{5}{3} x + 3 = \frac{1}{3} x - 3 \][/tex]

### Step 2: Solve for [tex]\(x\)[/tex]

Next, we solve for [tex]\(x\)[/tex]. First, we eliminate the fractions by multiplying every term by 3 to simplify the equation:
[tex]\[ -5x + 9 = x - 9 \][/tex]

Now, we move all the [tex]\(x\)[/tex]-terms to one side and the constant terms to the other side:
[tex]\[ -5x - x = -9 - 9 \][/tex]
[tex]\[ -6x = -18 \][/tex]

Divide both sides by -6 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = 3 \][/tex]

### Step 3: Solve for [tex]\(y\)[/tex]

Now that we have [tex]\(x = 3\)[/tex], we can substitute this value back into either of the original equations to find [tex]\(y\)[/tex]. We'll use the first equation:
[tex]\[ y = -\frac{5}{3} (3) + 3 \][/tex]

Simplify:
[tex]\[ y = -5 + 3 \][/tex]
[tex]\[ y = -2 \][/tex]

### Conclusion

The solution to the system of equations is the ordered pair [tex]\((x, y) = (3, -2)\)[/tex]. Therefore, the system has one solution, which is:
[tex]\[ \boxed{(3, -2)} \][/tex]