For the unsimplified sum, add the numerators and keep the denominator.
For the simplified sum, reduce the fraction to lowest terms.

\begin{tabular}{|c|l|l|}
\hline
Addition Problem & Unsimplified Sum & Simplified Sum \\
\hline
[tex]$\frac{3}{16}+\frac{5}{16}$[/tex] & [tex]$\frac{3+5}{16}$[/tex] & [tex]$\square$[/tex] \\
\hline
\end{tabular}



Answer :

Sure, let's go through the problem step-by-step.

### Step 1: Addition Problem
We start with the given fractions:
[tex]\[ \frac{3}{16} + \frac{5}{16} \][/tex]

### Step 2: Unsimplified Sum
Since both fractions have the same denominator, we can add the numerators directly and keep the denominator the same.

- Numerator: [tex]\(3 + 5 = 8\)[/tex]
- Denominator: [tex]\(16\)[/tex]

Thus, the unsimplified sum is:
[tex]\[ \frac{8}{16} \][/tex]

### Step 3: Simplified Sum
Next, we reduce the fraction [tex]\(\frac{8}{16}\)[/tex] to its lowest terms. This involves finding the greatest common divisor (GCD) of the numerator and the denominator and dividing both by this number.

- The GCD of 8 and 16 is 8.
- Simplified numerator: [tex]\(\frac{8}{8} = 1\)[/tex]
- Simplified denominator: [tex]\(\frac{16}{8} = 2\)[/tex]

Therefore, the simplified sum is:
[tex]\[ \frac{1}{2} \][/tex]

### Summary
Combining these steps, we fill in the table as follows:

[tex]\[ \begin{tabular}{|c|l|l|} \hline Addition Problem & Unsimplified Sum & Simplified Sum \\ \hline $\frac{3}{16}+\frac{5}{16}$ & $\frac{8}{16}$ & $\frac{1}{2}$ \\ \hline \end{tabular} \][/tex]