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A rectangular piece of iron has sides with lengths of [tex]$7.08 \times 10^{-3} \, \text{m}$[/tex], [tex]$2.18 \times 10^{-2} \, \text{m}$[/tex], and [tex][tex]$4.51 \times 10^{-3} \, \text{m}$[/tex][/tex]. What is the volume of the piece of iron?

A. [tex]6.96 \times 10^{-7} \, \text{m}^3[/tex]
B. [tex]6.96 \times 10^7 \, \text{m}^3[/tex]
C. [tex]6.96 \times 10^{-18} \, \text{m}^3[/tex]



Answer :

GinnyAnswer
To find the volume of a rectangular piece of iron, we use the formula for the volume of a rectangular prism:

[tex]\[ \text{Volume} = \text{length} \times \text{width} \times \text{height} \][/tex]

Given the dimensions of the rectangular piece of iron:
- Length [tex]\( \text{length} = 7.08 \times 10^{-3} \)[/tex] meters
- Width [tex]\( \text{width} = 2.18 \times 10^{-2} \)[/tex] meters
- Height [tex]\( \text{height} = 4.51 \times 10^{-3} \)[/tex] meters

Let's substitute these values into the formula:

[tex]\[ \text{Volume} = (7.08 \times 10^{-3}) \times (2.18 \times 10^{-2}) \times (4.51 \times 10^{-3}) \][/tex]

Carrying out this multiplication, we get:
[tex]\[ \text{Volume} = 6.9609144 \times 10^{-7} \][/tex]

After rounding this to the required significant figures as given in the answer choices, it matches:
[tex]\[ \text{Volume} \approx 6.96 \times 10^{-7} \, \text{m}^3 \][/tex]

Therefore, the correct answer is:
[tex]\[ 6.96 \times 10^{-7} \, \text{m}^3 \][/tex]

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