To determine the percent yield of ferrous sulfide given an actual yield of 220.0 grams and a theoretical yield of 275.6 grams, we will use the formula for percent yield:
[tex]\[
\text{Percent Yield} = \left( \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \right) \times 100
\][/tex]
We start by plugging in the given values for actual yield and theoretical yield into the formula:
[tex]\[
\text{Percent Yield} = \left( \frac{220.0 \, \text{g}}{275.6 \, \text{g}} \right) \times 100
\][/tex]
Next, we perform the division inside the parentheses:
[tex]\[
\frac{220.0}{275.6} \approx 0.7982583454281567
\][/tex]
Then, we multiply the result by 100 to convert it to a percentage:
[tex]\[
0.7982583454281567 \times 100 \approx 79.82583454281567
\][/tex]
Rounding this to two decimal places, we get:
[tex]\[
79.83\%
\][/tex]
Therefore, the percent yield of ferrous sulfide is [tex]\(\boxed{79.83\%}\)[/tex].
