A sound wave with a wavelength of 26 m passes through glass, and then it passes into air, where its wavelength changes to 1.6 m. If the sound wave has a constant frequency of 220 Hz, what is its approximate speed as it passes through the air? (The equation for the speed of a wave is [tex]$v = f \times \lambda$[/tex].)

A. [tex]$350 \, m/s$[/tex]
B. [tex][tex]$5,700 \, m/s$[/tex][/tex]
C. [tex]$570 \, m/s$[/tex]
D. [tex]$3,500 \, m/s$[/tex]



Answer :

To determine the speed of a sound wave as it passes through the air, we can use the equation for the speed of a wave, which is given by:

[tex]\[ v = f \times \lambda \][/tex]

where:
- [tex]\( v \)[/tex] is the speed of the wave,
- [tex]\( f \)[/tex] is the frequency of the wave,
- [tex]\( \lambda \)[/tex] is the wavelength of the wave.

We are given that:
- The frequency [tex]\( f \)[/tex] of the sound wave is 220 Hz,
- The wavelength [tex]\( \lambda \)[/tex] of the sound wave in air is 1.6 meters.

Let us substitute the given values into the wave speed equation:

[tex]\[ v = 220 \, \text{Hz} \times 1.6 \, \text{m} \][/tex]

[tex]\[ v = 352 \, \text{m/s} \][/tex]

Therefore, the speed of the sound wave as it passes through the air is approximately 352 m/s.

Given the options:
A. [tex]\( 350 \, \text{m/s} \)[/tex]
B. [tex]\( 5,700 \, \text{m/s} \)[/tex]
C. [tex]\( 570 \, \text{m/s} \)[/tex]
D. [tex]\( 3,500 \, \text{m/s} \)[/tex]

The closest value to our calculated speed is:

A. [tex]\( 350 \, \text{m/s} \)[/tex]

Thus, the correct answer is:
A. [tex]\( 350 \, \text{m/s} \)[/tex]