Answer :
Certainly! Let's solve the problem step-by-step:
We are asked to perform the division [tex]\(7 \longdiv {43.4}\)[/tex].
Step-by-Step Process:
1. Set up the division: We want to see how many times 7 fits into 43.4.
2. Consider the whole number part first:
- 7 goes into 43 six times because [tex]\(7 \times 6 = 42\)[/tex].
- Write 6 as the first digit of the quotient.
- Subtract 42 from 43, resulting in 1.
3. Bring down the next digit: After dealing with the integer part, we bring down the decimal part. Write down the decimal point in the quotient and bring down 4 to join the remainder 1, making it 14.
4. Divide the next part:
- 7 fits into 14 exactly 2 times because [tex]\(7 \times 2 = 14\)[/tex].
- Write 2 next to the 6 in the quotient.
- Subtract 14 from 14, resulting in 0.
Since there is no remainder and we have brought down all digits of 43.4, the division is complete.
The final result of [tex]\(7 \longdiv { 4 3 . 4 }\)[/tex] is:
[tex]\[6.2.\][/tex]
Thus, [tex]\( 43.4 \div 7 = 6.2 \)[/tex].
We are asked to perform the division [tex]\(7 \longdiv {43.4}\)[/tex].
Step-by-Step Process:
1. Set up the division: We want to see how many times 7 fits into 43.4.
2. Consider the whole number part first:
- 7 goes into 43 six times because [tex]\(7 \times 6 = 42\)[/tex].
- Write 6 as the first digit of the quotient.
- Subtract 42 from 43, resulting in 1.
3. Bring down the next digit: After dealing with the integer part, we bring down the decimal part. Write down the decimal point in the quotient and bring down 4 to join the remainder 1, making it 14.
4. Divide the next part:
- 7 fits into 14 exactly 2 times because [tex]\(7 \times 2 = 14\)[/tex].
- Write 2 next to the 6 in the quotient.
- Subtract 14 from 14, resulting in 0.
Since there is no remainder and we have brought down all digits of 43.4, the division is complete.
The final result of [tex]\(7 \longdiv { 4 3 . 4 }\)[/tex] is:
[tex]\[6.2.\][/tex]
Thus, [tex]\( 43.4 \div 7 = 6.2 \)[/tex].