Answer :
To calculate the number of moles of HCl in an 80.0 mL solution with a molarity of 0.500 M, we can follow these steps:
1. Convert the volume from milliliters (mL) to liters (L):
- The volume of the solution is given as 80.0 mL.
- Since 1 liter is equivalent to 1000 milliliters, we convert the volume by dividing by 1000:
[tex]\[ \text{Volume in liters (L)} = \frac{80.0 \text{ mL}}{1000} = 0.080 \text{ L} \][/tex]
2. Identify the molarity (M) of the solution:
- The molarity of the solution is given as 0.500 M.
- Molarity (M) represents the number of moles of solute (HCl in this case) per liter of solution.
3. Use the molarity formula to calculate the number of moles:
[tex]\[ \text{Moles of HCl} = \text{Molarity (M)} \times \text{Volume (L)} \][/tex]
- Substitute the given values into the formula:
[tex]\[ \text{Moles of HCl} = 0.500 \text{ M} \times 0.080 \text{ L} \][/tex]
4. Calculate the result:
[tex]\[ \text{Moles of HCl} = 0.500 \times 0.080 = 0.040 \text{ moles} \][/tex]
Therefore, the number of moles of HCl in 80.0 mL of a 0.500 M solution is [tex]\( 0.040 \)[/tex] moles.
1. Convert the volume from milliliters (mL) to liters (L):
- The volume of the solution is given as 80.0 mL.
- Since 1 liter is equivalent to 1000 milliliters, we convert the volume by dividing by 1000:
[tex]\[ \text{Volume in liters (L)} = \frac{80.0 \text{ mL}}{1000} = 0.080 \text{ L} \][/tex]
2. Identify the molarity (M) of the solution:
- The molarity of the solution is given as 0.500 M.
- Molarity (M) represents the number of moles of solute (HCl in this case) per liter of solution.
3. Use the molarity formula to calculate the number of moles:
[tex]\[ \text{Moles of HCl} = \text{Molarity (M)} \times \text{Volume (L)} \][/tex]
- Substitute the given values into the formula:
[tex]\[ \text{Moles of HCl} = 0.500 \text{ M} \times 0.080 \text{ L} \][/tex]
4. Calculate the result:
[tex]\[ \text{Moles of HCl} = 0.500 \times 0.080 = 0.040 \text{ moles} \][/tex]
Therefore, the number of moles of HCl in 80.0 mL of a 0.500 M solution is [tex]\( 0.040 \)[/tex] moles.