3. Simplify the given terms: - The volume conversion factor simplifies to [tex]\( 1 \text{mL} = 1000 \ \text{L} \)[/tex]: [tex]\[
\frac{1 \ \text{mL}}{10^{-3} \ \text{L}} = 1000 \ \text{mL/L}
\][/tex] - Therefore, the numerator will be: [tex]\[
117 \ \text{g} \times 1000 \ = 117000 \ \text{g \cdot mL/L}
\][/tex]
4. Set up the equation to solve for the missing part: The equation now looks like: [tex]\[
\frac{117000 \ [g \cdot mL/L]}{(53.40 \ [\square]) \left(1.8 \ \text{mol/L} \right)} = 1.2 \times 10^3 \ \text{mL}
\][/tex]
5. Rearrange to isolate the missing part: Solving for the missing part, we get: [tex]\[
53.40 \ [\square] = \frac{117000 \ [g \cdot mL/L]}{1.2 \times 10^3 \ [\text{mL}] \times 1.8 \ [\text{mol/L}]}
\][/tex] Simplify this: [tex]\[
53.40 [\square] = \frac{117000}{1.2 \times 10^3 \times 1.8}
\][/tex]
