Certainly! Let's find the value of [tex]\((2a - b)^2\)[/tex] when [tex]\(a = 4\)[/tex] and [tex]\(b = 3\)[/tex].
1. Substitute the given values into the expression:
[tex]\[
(2a - b)^2
\][/tex]
We know [tex]\(a = 4\)[/tex] and [tex]\(b = 3\)[/tex], so substituting these values, we get:
[tex]\[
(2 \cdot 4 - 3)^2
\][/tex]
2. Perform the operations inside the parentheses first:
[tex]\[
2 \cdot 4 = 8
\][/tex]
Thus, our expression now looks like:
[tex]\[
(8 - 3)^2
\][/tex]
3. Subtract inside the parentheses:
[tex]\[
8 - 3 = 5
\][/tex]
So the expression simplifies to:
[tex]\[
5^2
\][/tex]
4. Square the resulting number:
[tex]\[
5^2 = 25
\][/tex]
Therefore, the value of [tex]\((2a - b)^2\)[/tex] when [tex]\(a = 4\)[/tex] and [tex]\(b = 3\)[/tex] is [tex]\(\boxed{25}\)[/tex].
