Answer :
Sure! Let's break down each question and solve them step-by-step:
### Question 8:
A tricycle travelled at a steady speed of 18 km/h for [tex]\(2 \frac{1}{2}\)[/tex] hours. What is the distance covered by the tricycle?
1. 35 km
B. 45 km
C. 55 km
D. 75 km
Step-by-Step Solution:
1. Convert the given time: [tex]\(2 \frac{1}{2}\)[/tex] hours is equivalent to [tex]\(2 + \frac{1}{2}\)[/tex] hours, which is equal to 2.5 hours.
2. Use the formula for distance: Distance [tex]\(=\)[/tex] Speed [tex]\(\times\)[/tex] Time.
3. Calculate the distance: [tex]\(18 \text{ km/h} \times 2.5 \text{ hours} = 45 \text{ km}\)[/tex].
Answer:
The distance covered by the tricycle is 45 km.
### Question 9:
Find correct to 3 decimal places, the number whose logarithm is 0.6111.
^. 4.083
B. 4.084
C. 7.853
D. 7.861
Step-by-Step Solution:
1. Identify the given logarithm value: 0.6111.
2. Determine the corresponding number using the antilogarithm (base 10): [tex]\(10^{0.6111}\)[/tex].
3. Calculate the value: The number corresponding to a logarithm of 0.6111 is 4.084 (rounded to 3 decimal places).
Answer:
The number whose logarithm is 0.6111 is 4.084.
### Question 10:
Express 1.2 kg as a percentage of 1.5 kg.
^. [tex]$1 \frac{4}{5}\%$[/tex]
B. [tex]$8\%$[/tex]
C. [tex]$80\%$[/tex]
Step-by-Step Solution:
1. Identify the given weights:
- Part weight: 1.2 kg.
- Whole weight: 1.5 kg.
2. Use the percentage formula: [tex]\(\left(\frac{\text{part}}{\text{whole}}\right) \times 100\)[/tex].
3. Calculate the percentage: [tex]\(\left(\frac{1.2 \text{ kg}}{1.5 \text{ kg}}\right) \times 100 = 80\%\)[/tex].
Answer:
1.2 kg as a percentage of 1.5 kg is 80%.
---
In summary:
- For the tricycle question, the distance covered is [tex]\(45\)[/tex] km.
- The number whose logarithm is [tex]\(0.6111\)[/tex] is [tex]\(4.084\)[/tex].
- [tex]\(1.2\)[/tex] kg as a percentage of [tex]\(1.5\)[/tex] kg is [tex]\(80\%\)[/tex].
### Question 8:
A tricycle travelled at a steady speed of 18 km/h for [tex]\(2 \frac{1}{2}\)[/tex] hours. What is the distance covered by the tricycle?
1. 35 km
B. 45 km
C. 55 km
D. 75 km
Step-by-Step Solution:
1. Convert the given time: [tex]\(2 \frac{1}{2}\)[/tex] hours is equivalent to [tex]\(2 + \frac{1}{2}\)[/tex] hours, which is equal to 2.5 hours.
2. Use the formula for distance: Distance [tex]\(=\)[/tex] Speed [tex]\(\times\)[/tex] Time.
3. Calculate the distance: [tex]\(18 \text{ km/h} \times 2.5 \text{ hours} = 45 \text{ km}\)[/tex].
Answer:
The distance covered by the tricycle is 45 km.
### Question 9:
Find correct to 3 decimal places, the number whose logarithm is 0.6111.
^. 4.083
B. 4.084
C. 7.853
D. 7.861
Step-by-Step Solution:
1. Identify the given logarithm value: 0.6111.
2. Determine the corresponding number using the antilogarithm (base 10): [tex]\(10^{0.6111}\)[/tex].
3. Calculate the value: The number corresponding to a logarithm of 0.6111 is 4.084 (rounded to 3 decimal places).
Answer:
The number whose logarithm is 0.6111 is 4.084.
### Question 10:
Express 1.2 kg as a percentage of 1.5 kg.
^. [tex]$1 \frac{4}{5}\%$[/tex]
B. [tex]$8\%$[/tex]
C. [tex]$80\%$[/tex]
Step-by-Step Solution:
1. Identify the given weights:
- Part weight: 1.2 kg.
- Whole weight: 1.5 kg.
2. Use the percentage formula: [tex]\(\left(\frac{\text{part}}{\text{whole}}\right) \times 100\)[/tex].
3. Calculate the percentage: [tex]\(\left(\frac{1.2 \text{ kg}}{1.5 \text{ kg}}\right) \times 100 = 80\%\)[/tex].
Answer:
1.2 kg as a percentage of 1.5 kg is 80%.
---
In summary:
- For the tricycle question, the distance covered is [tex]\(45\)[/tex] km.
- The number whose logarithm is [tex]\(0.6111\)[/tex] is [tex]\(4.084\)[/tex].
- [tex]\(1.2\)[/tex] kg as a percentage of [tex]\(1.5\)[/tex] kg is [tex]\(80\%\)[/tex].