The regular price of a shirt at a store is $11.70. The sale price of the shirt is 80% less than the regular price, and the sale price is 30% greater than the store's cost for the shirt. What was the store's cost, in dollars, for the shirt?



Answer :

Let's break down the problem step-by-step to find the store's cost for the shirt.

### Step 1: Determine the Sale Price

The regular price of the shirt is [tex]$11.70. The sale price is described as being 80% less than the regular price. To find the sale price: 1. Calculate 80% of the regular price: \[ 0.80 \times 11.70 = 9.36 \] 2. Subtract this amount from the regular price: \[ 11.70 - 9.36 = 2.34 \] So, the sale price of the shirt is $[/tex]2.34.

### Step 2: Relate the Sale Price to the Store's Cost

The sale price is also described as being 30% greater than the store's cost. We can express this relationship with the following equation:

[tex]\[ \text{Sale Price} = \text{Store's Cost} + 0.30 \times \text{Store's Cost} \][/tex]
[tex]\[ \text{Sale Price} = 1.30 \times \text{Store's Cost} \][/tex]

We already know the sale price is [tex]$2.34. Let \( x \) be the store's cost. Using the sale price equation: \[ 2.34 = 1.30 \times x \] ### Step 3: Solve for the Store's Cost To isolate \( x \), divide both sides of the equation by 1.30: \[ x = \frac{2.34}{1.30} \] \[ x \approx 1.80 \] So, the store's cost for the shirt was approximately $[/tex]1.80.

### Summary

By following these steps, we found:

1. The sale price of the shirt is [tex]$2.34. 2. This sale price is 30% greater than the store's cost. 3. Therefore, the store's cost is approximately $[/tex]1.80.

So, the store's cost in dollars for the shirt is $1.80.