Select the correct answer.

A florist makes a string of flowers along a pole and ties it at a point 20 feet high on the wall and to the floor 8 feet away from the wall. He then changes his mind and moves the flowers down the wall 10 feet.

Approximately how far away from the wall would he now have to tie the flowers on the floor?

A. [tex]15.4 \, \text{ft}[/tex]
B. [tex]19.1 \, \text{ft}[/tex]
C. [tex]23.7 \, \text{ft}[/tex]
D. [tex]21.5 \, \text{ft}[/tex]



Answer :

Let's go through this problem step by step.

1. Initial Setup:
- The initial height at which the string of flowers is tied on the wall is 20 feet.
- The distance from the wall to the point where the string is tied on the floor is 8 feet.

2. Calculating the Original Length of the String:
- We use the Pythagorean theorem: [tex]\( a^2 + b^2 = c^2 \)[/tex].
- Here, [tex]\( a \)[/tex] is the height (20 feet), [tex]\( b \)[/tex] is the distance from the wall (8 feet), and [tex]\( c \)[/tex] is the length of the string.
- So, [tex]\( c = \sqrt{20^2 + 8^2} \)[/tex].
- This gives [tex]\( c \approx 21.54 \)[/tex] feet.

3. New Setup:
- The height at which the string of flowers is now tied on the wall is 10 feet.
- The length of the string remains the same, so it is still approximately 21.54 feet.

4. Calculating the New Distance From the Wall:
- Using the Pythagorean theorem again, but solving for the distance from the wall:
- Let [tex]\( d \)[/tex] be the new distance from the wall. Then, [tex]\( d \)[/tex] should satisfy the equation [tex]\( 10^2 + d^2 = (21.54)^2 \)[/tex].
- Rearranging for [tex]\( d \)[/tex], we get [tex]\( d = \sqrt{(21.54)^2 - 10^2} \)[/tex].
- This gives [tex]\( d \approx 19.08 \)[/tex] feet.

Therefore, the new distance from the wall where the string would be tied is approximately [tex]\( 19.1 \)[/tex] feet.

So, the correct answer is:
B. [tex]\( 19.1 \)[/tex] feet