Rewrite each equation as requested.

(a) Rewrite as an exponential equation.

[tex]\[
\log _8 1=0
\][/tex]

(b) Rewrite as a logarithmic equation.

[tex]\[
3^4=81
\][/tex]

(a) [tex]\(\square = \square\)[/tex]

(b) [tex]\(\log _{\square} \square = \square\)[/tex]



Answer :

Sure, let's rewrite each equation as requested, step by step.

### Part (a) Rewrite as an exponential equation

Given the logarithmic equation:
[tex]\[ \log_8 1 = 0 \][/tex]

We need to convert this to an exponential equation. Recall the definition of a logarithm: [tex]\(\log_b a = c\)[/tex] is equivalent to [tex]\(b^c = a\)[/tex].

In this case:
[tex]\[ \log_8 1 = 0 \][/tex]

Using the logarithm definition:
[tex]\[ 8^0 = 1 \][/tex]

So, the exponential form of [tex]\(\log_8 1 = 0\)[/tex] is:
[tex]\[ 8^0 = 1 \][/tex]

### Part (b) Rewrite as a logarithmic equation

Given the exponential equation:
[tex]\[ 3^4 = 81 \][/tex]

We need to convert this to a logarithmic equation. Recall that [tex]\(b^c = a\)[/tex] is equivalent to [tex]\(\log_b a = c\)[/tex].

In this case:
[tex]\[ 3^4 = 81 \][/tex]

Using the exponential to logarithm conversion rule:
[tex]\[ \log_3 81 = 4 \][/tex]

So, the logarithmic form of [tex]\(3^4 = 81\)[/tex] is:
[tex]\[ \log_3 81 = 4 \][/tex]

### Final Answers:
(a) [tex]\(8^0 = 1\)[/tex]

(b) [tex]\(\log_3 81 = 4\)[/tex]

So, filling in:

(a) [tex]\(8^0 = 1\)[/tex]

(b) [tex]\(\log_3 81 = 4\)[/tex]