Select the correct answer.

What is the value of the expression when [tex]$a=-2, b=3$, and $c=-6$[/tex]?

[tex]\frac{a b + 2 c}{-b c}[/tex]



Answer :

To find the value of the expression [tex]\(\frac{a b + 2 c}{-b c}\)[/tex], we need to follow these steps:

1. Substitute the given values into the expression:
- [tex]\(a = -2\)[/tex]
- [tex]\(b = 3\)[/tex]
- [tex]\(c = -6\)[/tex]

2. Calculate [tex]\(a b + 2 c\)[/tex]:
- First, calculate [tex]\(a b\)[/tex]:
[tex]\[ a \cdot b = -2 \cdot 3 = -6 \][/tex]
- Next, calculate [tex]\(2 c\)[/tex]:
[tex]\[ 2 \cdot c = 2 \cdot -6 = -12 \][/tex]
- Now, add the two results together:
[tex]\[ a b + 2 c = -6 + (-12) = -18 \][/tex]

3. Calculate the denominator, [tex]\(-b c\)[/tex]:
- First, calculate [tex]\(b c\)[/tex]:
[tex]\[ b \cdot c = 3 \cdot -6 = -18 \][/tex]
- Then apply the negative sign:
[tex]\[ -b c = -(-18) = 18 \][/tex]

4. Evaluate the entire expression:
[tex]\[ \frac{a b + 2 c}{-b c} = \frac{-18}{18} = -1.0 \][/tex]

Thus, the value of the expression is [tex]\(-1.0\)[/tex].