Transform the ratio into the corresponding numbers and prepare a complete table for the following data. Give a suitable title to the table.

In the year 2000, the total strength of students in three colleges [tex]\(X\)[/tex], [tex]\(Y\)[/tex], and [tex]\(Z\)[/tex] in a city was in the ratio [tex]\(2:5\)[/tex].

(Note: There is some information missing here. Please specify the total number of students or the individual strengths of colleges to complete the table accurately.)



Answer :

## Distribution of Students in Colleges in the Year 2000

In the year 2000, the total student strength of three colleges, denoted as [tex]\(X\)[/tex], [tex]\(Y\)[/tex], and [tex]\(Z\)[/tex], in a city were in the ratio [tex]\(2:5:1\)[/tex]. To determine the number of students in each college, we follow the given ratio and assume a common factor [tex]\(k\)[/tex] which represents the multiple of the ratio parts.

Let’s break down the problem step-by-step.

### Given Ratios

1. College [tex]\(X\)[/tex]: [tex]\(2\)[/tex] parts
2. College [tex]\(Y\)[/tex]: [tex]\(5\)[/tex] parts
3. College [tex]\(Z\)[/tex]: [tex]\(1\)[/tex] part

### Total Parts

The total parts representing all students across the three colleges is:
[tex]\[ \text{Total Parts} = 2 + 5 + 1 = 8 \][/tex]

### Determining Student Strengths

Using the ratio parts, we can determine the number of students in each college if we assume the simplest multiple [tex]\(k = 1\)[/tex].

1. Students in College [tex]\(X\)[/tex] (Strength [tex]\(X\)[/tex]):
[tex]\[ \text{Strength}_X = 2 \times k = 2 \times 1 = 2 \][/tex]

2. Students in College [tex]\(Y\)[/tex] (Strength [tex]\(Y\)[/tex]):
[tex]\[ \text{Strength}_Y = 5 \times k = 5 \times 1 = 5 \][/tex]

3. Students in College [tex]\(Z\)[/tex] (Strength [tex]\(Z\)[/tex]):
[tex]\[ \text{Strength}_Z = 1 \times k = 1 \times 1 = 1 \][/tex]

### Total Strength

The total strength of students in all the colleges can be calculated by summing the individual strengths:
[tex]\[ \text{Total Strength} = \text{Strength}_X + \text{Strength}_Y + \text{Strength}_Z \][/tex]
[tex]\[ \text{Total Strength} = 2 + 5 + 1 = 8 \][/tex]

### Table of Distribution

Below is the complete table summarizing the number of students in each college based on the provided ratio:

| College | Strength (Number of Students) |
|-----------------|-------------------------------|
| College [tex]\(X\)[/tex] | 2 |
| College [tex]\(Y\)[/tex] | 5 |
| College [tex]\(Z\)[/tex] | 1 |
| Total | 8 |

This table shows the distribution of students in the three colleges in the year 2000, maintaining the given ratio of [tex]\(2:5:1\)[/tex].