The width of a 2-by-4 piece of wood is actually [tex]3 \frac{1}{2}[/tex] inches. Find the total width of 28 2-by-4s laid side-by-side. Simplify your answer.

A. 98 inches
B. [tex]\frac{196}{2}[/tex] inches
C. [tex]84 \frac{1}{2}[/tex] inches
D. 784 inches



Answer :

To find the total width of 28 2-by-4 pieces of wood, each with a width of [tex]\(3 \frac{1}{2}\)[/tex] inches when laid side-by-side, we will proceed as follows:

1. Convert the mixed number to an improper fraction:
The width of one board is given as [tex]\(3 \frac{1}{2}\)[/tex] inches. We can convert this mixed number to an improper fraction.

[tex]\[ 3 \frac{1}{2} = 3 + \frac{1}{2} = \frac{6}{2} + \frac{1}{2} = \frac{7}{2} \text{ inches} \][/tex]

2. Multiply by the number of boards:
We are laying 28 boards side-by-side. To find the total width, we multiply the width of one board by the number of boards.

[tex]\[ \frac{7}{2} \times 28 \][/tex]

3. Perform the multiplication:
Simplify the multiplication as follows:

[tex]\[ \frac{7}{2} \times 28 = 7 \times 14 = 98 \text{ inches} \][/tex]

The total width of the 28 boards laid side-by-side is 98 inches.

4. Convert to a different fraction form:
We can express 98 inches in different fraction forms. One such form is:

[tex]\[ 98 = \frac{196}{2} \text{ inches} \][/tex]

Hence, we see that the total width of the 28 2-by-4s laid side-by-side can be represented in various forms, such as:
- [tex]\( 98 \text{ inches} \)[/tex]
- [tex]\( \frac{196}{2} \text{ inches} \)[/tex]

And as simplification is requested in some formats:
- Simplified form as an improper fraction: [tex]\( 98 \text{ inches} \)[/tex]

Therefore, the total width of 28 2-by-4s laid side-by-side is:

98 inches

or, equivalently,

[tex]\( \frac{196}{2} \text{ inches} \)[/tex].