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If [tex]x \ \textgreater \ 0[/tex], what is the difference of [tex]6x \sqrt{14x} - 5\sqrt{56x^3}[/tex] in simplest form?



Answer :

To find the difference [tex]\( 6 x \sqrt{14 x} - 5 \sqrt{56 x^3} \)[/tex] in simplest form, let's break it down step by step.

1. Simplify each part of the expression:

- For [tex]\( 6 x \sqrt{14 x} \)[/tex]:
[tex]\[ 6 x \sqrt{14 x} \][/tex]
Recognize that [tex]\( \sqrt{14 x} = \sqrt{14} \cdot \sqrt{x} \)[/tex], so:
[tex]\[ 6 x \sqrt{14 x} = 6 x \cdot \sqrt{14} \cdot \sqrt{x} = 6 \sqrt{14} \cdot x \cdot x^{1/2} = 6 \sqrt{14} \cdot x^{3/2} \][/tex]
Thus, the simplified form of [tex]\( 6 x \sqrt{14 x} \)[/tex] is:
[tex]\[ 6 \sqrt{14} \cdot x^{3/2} \][/tex]

- For [tex]\( 5 \sqrt{56 x^3} \)[/tex]:
[tex]\[ 5 \sqrt{56 x^3} \][/tex]
Recognize that [tex]\( 56 x^3 = 56 \cdot x^3 \)[/tex] and [tex]\( \sqrt{56 x^3} = \sqrt{56} \cdot \sqrt{x^3} \)[/tex]. Also, [tex]\( \sqrt{x^3} = x^{3/2} \)[/tex], so:
[tex]\[ 5 \sqrt{56 x^3} = 5 \sqrt{56} \cdot x^{3/2} \][/tex]
Now, [tex]\( 56 = 4 \cdot 14 \)[/tex] and [tex]\( \sqrt{56} = \sqrt{4 \cdot 14} = \sqrt{4} \cdot \sqrt{14} = 2 \sqrt{14} \)[/tex], thus:
[tex]\[ 5 \sqrt{56} \cdot x^{3/2} = 5 \cdot 2 \sqrt{14} \cdot x^{3/2} = 10 \sqrt{14} \cdot x^{3/2} \][/tex]
So, the simplified form of [tex]\( 5 \sqrt{56 x^3} \)[/tex] is:
[tex]\[ 10 \sqrt{14} \cdot x^{3/2} \][/tex]

2. Find the difference of the simplified expressions:
[tex]\[ 6 \sqrt{14} \cdot x^{3/2} - 10 \sqrt{14} \cdot x^{3/2} \][/tex]

3. Combine like terms:
Both terms have the common factor [tex]\( \sqrt{14} \cdot x^{3/2} \)[/tex]:
[tex]\[ (6 \sqrt{14} \cdot x^{3/2}) - (10 \sqrt{14} \cdot x^{3/2}) \][/tex]
Factor out [tex]\( \sqrt{14} \cdot x^{3/2} \)[/tex]:
[tex]\[ \left(6 - 10\right) \sqrt{14} \cdot x^{3/2} = -4 \sqrt{14} \cdot x^{3/2} \][/tex]

Therefore, the difference of [tex]\( 6 x \sqrt{14 x} - 5 \sqrt{56 x^3} \)[/tex] in simplest form is:
[tex]\[ -4 \sqrt{14} \cdot x^{3/2} \][/tex]