The yearly attendance at a ballpark is shown in the table below.

Which answer describes the average rate of change from Year 2 to Year 5?

\begin{tabular}{|c|c|}
\hline
Year & \begin{tabular}{c}
Attendance \\
(thousands)
\end{tabular} \\
\hline
1 & 327.5 \\
\hline
2 & 298.3 \\
\hline
3 & 356.8 \\
\hline
4 & 397.2 \\
\hline
5 & 333.7 \\
\hline
\end{tabular}

A. Attendance increased by an average of 35,400 people per year from Year 2 to Year 5.

B. Attendance decreased by an average of 35,400 people per year from Year 2 to Year 5.

C. Attendance increased by an average of 11,800 people per year from Year 2 to Year 5.

D. Attendance decreased by an average of 11,800 people per year from Year 2 to Year 5.



Answer :

To determine the average rate of change in attendance from Year 2 to Year 5, we will follow these steps:

1. Identify the attendance values for the specified years:
- Year 2 attendance: 298.3 thousand people.
- Year 5 attendance: 333.7 thousand people.

2. Determine the time interval:
- The number of years between Year 2 and Year 5 is [tex]\( 5 - 2 = 3 \)[/tex] years.

3. Calculate the difference in attendance between Year 5 and Year 2:
- Change in attendance = [tex]\( 333.7 - 298.3 = 35.4 \)[/tex] thousand people.

4. Calculate the average rate of change:
- Average rate of change in attendance per year = [tex]\( \frac{\text{Change in attendance}}{\text{Number of years}} \)[/tex]
- Average rate of change = [tex]\( \frac{35.4 \text{ thousand people}}{3 \text{ years}} = 11.8 \text{ thousand people per year} \)[/tex].

Given these calculations, the average rate of change in attendance from Year 2 to Year 5 is 11,800 people increased per year. The correct answer is:

Attendance increased by an average of 11,800 people per year from Year 2 to Year 5.