What is the range of [tex]$g(x)=\left\{\begin{array}{cc}x^2-5, & x\ \textless \ 2 \\ 2x, & x \geq 2\end{array}\right.$[/tex]?



Answer :

To find the range of the piecewise function [tex]\( g(x) \)[/tex], defined as

[tex]\[ g(x) = \begin{cases} x^2 - 5 & \text{if } x < 2 \\ 2x & \text{if } x \geq 2 \end{cases} \][/tex]

we will analyze each piece separately and then combine the results to obtain the overall range of the function.

### Step 1: Analyzing [tex]\( g(x) = x^2 - 5 \)[/tex] for [tex]\( x < 2 \)[/tex]

First, let's consider the part of the function for [tex]\( x < 2 \)[/tex].

- The quadratic function [tex]\( x^2 - 5 \)[/tex] is a parabola that opens upward with its vertex at the point [tex]\( x = 0 \)[/tex].
- Evaluating the function at the vertex, we find that [tex]\( g(0) = 0^2 - 5 = -5 \)[/tex].

As [tex]\( x \)[/tex] moves away from 0, either towards negative infinity or approaching [tex]\( x = 2 \)[/tex] from the left, the value of [tex]\( x^2 - 5 \)[/tex] increases.

- The function is continuous and by looking at the end values, we observe:
- As [tex]\( x \)[/tex] approaches -∞, [tex]\( g(x) = x^2 - 5 \)[/tex] approaches ∞.
- As [tex]\( x \)[/tex] approaches 2 from the left, we get [tex]\( g(2^-) = 2^2 - 5 = -1 \)[/tex].

So, for [tex]\( x < 2 \)[/tex], the minimum value of [tex]\( g(x) \)[/tex] is -5 (occuring at [tex]\( x = 0 \)[/tex]), and it can grow indefinitely large as [tex]\( x \)[/tex] moves towards -∞. Therefore, the range of this part is [tex]\((-5, \infty)\)[/tex].

### Step 2: Analyzing [tex]\( g(x) = 2x \)[/tex] for [tex]\( x \ge 2 \)[/tex]

Next, consider when [tex]\( x \geq 2 \)[/tex]:

- For [tex]\( x \ge 2 \)[/tex], the function [tex]\( g(x) = 2x \)[/tex] is a linear function with a constant positive slope of 2.
- Evaluating the function as [tex]\( x \)[/tex] increases:
- At [tex]\( x = 2 \)[/tex], [tex]\( g(2) = 2 \cdot 2 = 4 \)[/tex].
- As [tex]\( x \)[/tex] approaches positive infinity, [tex]\( g(x) = 2x \)[/tex] also approaches positive infinity.

Therefore, for [tex]\( x \ge 2 \)[/tex], the range starts at 4 and extends indefinitely upwards. Thus, the range is [tex]\([4, \infty)\)[/tex].

### Step 3: Combine the ranges

To determine the overall range of the function [tex]\( g(x) \)[/tex], we combine the ranges from each piece:

- For [tex]\( x \ge 2 \)[/tex]: [4, ∞)
- For [tex]\( x < 2 \)[/tex]: [tex]\((-5, \infty)\)[/tex]

Since the pieces overlap in the interval [tex]\([4, ∞)\)[/tex], we combine them:

The overall range of the function [tex]\( g(x) \)[/tex] is [tex]\((-5, \infty)\)[/tex].