Answer :
Certainly! Let’s walk through the steps to find the value of Erica's investment after 6 years.
### Initial Setup
1. Initial Investment (Principal): Erica invested [tex]$4000 initially. 2. Annual Growth Rate: The value of her investment grows at an annual rate of 4%. This translates to a growth multiplier of \( 1 + 0.04 = 1.04 \). 3. Time (t): The investment duration is 6 years. ### Formula for Compound Interest The formula to calculate the future value of an investment compounded annually is given by: \[ y = P (1 + r)^t \] where: - \( y \) is the future value of the investment. - \( P \) is the principal amount (initial investment). - \( r \) is the annual growth rate (expressed as a decimal). - \( t \) is the time in years. ### Plugging in the Values Using the values provided: - \( P = 4000 \) - \( r = 0.04 \) (which is 4% expressed as a decimal) - \( t = 6 \) Substitute these into the formula: \[ y = 4000 (1 + 0.04)^6 \] \[ y = 4000 (1.04)^6 \] ### Calculating the Growth Factor Next, calculate \( (1.04)^6 \). Using a calculator for precision: \[ (1.04)^6 = 1.265319 \] ### Calculating the Future Value Now, multiply the initial investment by the growth factor: \[ y = 4000 \times 1.265319 \] Perform the multiplication: \[ y = 5061.276 \] ### Conclusion Therefore, the value of Erica's investment after 6 years will be approximately $[/tex]5061.28.
Erica’s investment grows to \$5061.28 over a period of 6 years at an annual growth rate of 4%.
### Initial Setup
1. Initial Investment (Principal): Erica invested [tex]$4000 initially. 2. Annual Growth Rate: The value of her investment grows at an annual rate of 4%. This translates to a growth multiplier of \( 1 + 0.04 = 1.04 \). 3. Time (t): The investment duration is 6 years. ### Formula for Compound Interest The formula to calculate the future value of an investment compounded annually is given by: \[ y = P (1 + r)^t \] where: - \( y \) is the future value of the investment. - \( P \) is the principal amount (initial investment). - \( r \) is the annual growth rate (expressed as a decimal). - \( t \) is the time in years. ### Plugging in the Values Using the values provided: - \( P = 4000 \) - \( r = 0.04 \) (which is 4% expressed as a decimal) - \( t = 6 \) Substitute these into the formula: \[ y = 4000 (1 + 0.04)^6 \] \[ y = 4000 (1.04)^6 \] ### Calculating the Growth Factor Next, calculate \( (1.04)^6 \). Using a calculator for precision: \[ (1.04)^6 = 1.265319 \] ### Calculating the Future Value Now, multiply the initial investment by the growth factor: \[ y = 4000 \times 1.265319 \] Perform the multiplication: \[ y = 5061.276 \] ### Conclusion Therefore, the value of Erica's investment after 6 years will be approximately $[/tex]5061.28.
Erica’s investment grows to \$5061.28 over a period of 6 years at an annual growth rate of 4%.